Recognizing features of functions (example 2) | Algebra II | Khan Academy

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Algebra II on Khan Academy: Your studies in algebra 1 have built a solid foundation from which you can explore linear equations, inequalities, and functions. In algebra 2 we build upon that foundation and not only extend our knowledge of algebra 1, but slowly become capable of tackling the BIG questions of the universe. We'll again touch on systems of equations, inequalities, and functions...but we'll also address exponential and logarithmic functions, logarithms, imaginary and complex numbers, conic sections, and matrices. Don't let these big words intimidate you. We're on this journey with you!

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[michaelhaggerty]

3:44 lmfaoo 
"The math problem, not the car crash"

[figureyou]

I enjoyed both the car crash and the math problem

[Kram]

This video is very old school Sal: "A car crash happened? Oh well, I'll put up the video anyway"

[LeEnnyFace]

it was sal's roof, by the way. not a car crash

[ChichaandHerobrine]

Lol, the car crash. I hope everyone's okay there, although it sound pretty bad.

[Kram]

It's neither. Though you can turn it into an even or odd function like this:
(f(x)+f(-x))/2 - is even
(f(x)-f(-x))/2 - is odd.
However, since this is a linear function f(x)=k x + d, if you do this for the given function, you'll just get:
((k x + d) + (k (-x) + d) )/2=(k (x-x) + d + d)/2 = d, a constant function
((k x + d) - (k (-x) + d)/2 = (k (x+x) + d - d)/2 = k x, line with 0 y-intercept.
those represent the simplest possible, respectively even and odd functions.

[ThalesPo]

I enjoy car crashes. You should have gone outside to show that.