Statics Problems | 2-1 to 2-8 |Resolution of vectors into Rectangular Components | Engineers Academy

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STATICS | Chapter 2 | P 2-1 to P 2-8 Solution | Rectangular Components | Engineers Academy
Chapter 2: Force Systems
Resolution of Force into Components
Problems Solution
0:00 2/1 The force F has a magnitude of 800 N. Express F as a vector in terms of the unit vectors i and j. Identify the x and y scalar components of F.

4:00 2/2 The magnitude of the force F is 600 N. Express F as a vector in terms of the unit vectors i and j. Identify both the scalar and vector components of F.

6:15 2/3 The slope of the 4.8-kN force F is specified as shown in the figure. Express F as a vector in terms of the unit vectors i and j.

9:20 2/4 The line of action of the 9.6-kN force F runs through the points A and B as shown in the figure. Determine the x and y scalar components of F.

15:37 2/5 A cable stretched between the fixed supports A and B is under a tension T of 900 N. Express the tension as a vector using the unit vectors i and j, first, as a force TA acting on A and second, as a force TB acting on B.

20:27 2/6 The 1800-N force F is applied to the end of the I beam. Express F as a vector using the unit vectors i and j.

23:10 2/7 The two structural members, one of which is in tension and the other in compression, exert the indicated forces on joint O. Determine the magnitude of the resultant R of the two forces and the angle which R makes with the positive x-axis.

29:14 2/8 Two forces are applied to the construction bracket as shown. Determine the angle which makes the resultant of the two forces vertical. Determine the magnitude R of the resultant.

Resolution of vectors
how to resolve a given vector
rectangular components
x and y components of a vector
how to find resultant

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Resolution of vectors
Resolution of vectors into Rectangular Components Hibbeler Statics - Chapter Playlists

[EngineersAcademy]

Kindly like, share and express your views in the comments. Thanks.

[dagememnete]

on the 7th question, angle teta is 26.2, and keep up the good work

[nooralhudaraad]

Hello, I am of Arab origin, and I found your channel and found it very useful for me because I study engineering, but there is a problem with the language and there is no translation for the videos.

[rasuol]

Thank you very much, creator. I am very happy that you translated the video into Arabic ❤️

[bhoominathan]

Your videos are more useful for teachers as well as students

[dargaimalakand]

Good Job, true teacher of statics.
Also start making videos of MOM-1(Mechanics of material)/solid mechanics.
I can share problems(questions) with you, which are taught in Mechanical department, UET Peshawar.

[NtlakuBaloyi]

i would like to thank you for helping me understand this better

[BuniyaminuIsah]

I want to say thank you from Nigeria (Africa)for helping me in my exams particularly on applied mechanics.
But in another case, I'm struggling with thermodynamics and I wish there was a YouTube channel for that like yours or do you know any????

[saifyousafzai]

Great work sir 👌👌👌We waited a long for this subject...Thanks a lot sir 😇

[haftuberhe]

simple way explanation sir thank you but also for 8th edition pleas

[muhammadmusa]

Thanks you Sir for such simple explanation.

[doubleice]

Sir! can i ask a quick question around 28:26 mark. How does the angle became 206 degrees? As i solved tan-1(-1.598/-3.23) the result shows 26.3232 ?

[User-dbhs]

Thank you so much sir🙏🙏These videos are very helpful.

[ghusharibabbas]

Sir how the theeta value is 206 degree in numarical 7 ...i need to know because even after conversion to degrees my calculator shows 26.3

[sheherbano]

A.o.a sir I have a question. Can I ask you? The question is about the problem 2/8. My question is that the direction of F2x and F1x is towards each other at the center (point O), why? Shouldn’t we apply head to tail rule here to draw Fxs? I mean the direction of F2x and F1x opposite to each other (away from the center).

[samtenwangmo]

Thank you it was helpful and understanding keep it up la...

[MuhammadAnwar-izxz]

thank you sir... It is very helpful for us.... Sir upload more numericals also. . . .thanks

[danyalshafiq]

Sir you are Doing a Great job ❤
Sir I have question in 2/4 problem
How can you take the coordinates of C like (300 and -100) ? any Special Thinking? kindly clear it to me 😊❤

[hashamnoor]

Can some recommend me a video related to find when (Fx get cos) or (Fx=Fcos0) or when Fy=Fcos0 when angle is not given

[deepushah]

A beam with length of 1 m is supported at both ends by a pin constraint. The beam is subject to a
distributed load with triangular shape from x=0 (position of the left constraint) to x1=0.5 m, with
maximum value f=60 N/m reached at x1=0.5 m. Then, an additional distributed load with triangular
shape acts from x1 to x2=0.8 m, in which the magnitude decreases from f=60 N/m (at x1) to zero (at x2).
(a) Sketch the free body diagram of the system.

(b) Determine magnitude and position of the equivalent concentrated loads
for the distributed loads.

(c) Determine the constraint reactions at both constraints.

(d) Now, assume a value of 8 kg for the mass of the beam. Determine the
constraint reactions for the same configuration (with the distributed
loads as described above), taking into account the weight of the beam
(assume homogeneous material across the whole length of the beam).

Can you make it for me plzxx