Derivative of cosh^-1(x), two ways

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We will find the derivative of inverse hyperbolic cosine in two ways.

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I want that shirt. Wait, no, I want the person in front of me to have that shirt.

kingbeauregard
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Derivative of arccosh x is -arcsinh x *dabs*

futfan
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this video just saved me from depression

lekonokago
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are students allowed to wear that shirt during tests? xD

BigDBrian
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I liked the second one... don't know, I have always liked more implicit (don't know how to write it) derivatives... Great video!

YourPhysicsSimulator
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Can you do a video of this showing the general equation for the derivative cosh^-1x?

nvapisces
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Does anyone have the link for buying that t-shirt

PhilipLabelle
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Do You Wear this shirt when you are invigilator in any exam?

purushotamgarg
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Hello sir from india how we will solve underroot r4-a4 please answer

tanuyadav
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I had an idea for a video on a "concatenate" operator, a function that just puts 2 things together. For example, concat(2, 2) = 22, concat(47, 299) = 47299, etc.
I'm not sure how to derive a function for this, and it may be interesting.

JoJoJet
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how are you able to rewrite cosh^-1 to ln(x+sqrt(x^2-1)? I didn't now that is a thing

PlainVas
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The third way is to use that cosh(x) = cos(ix), thus cosh^-1(x) = -i cos^-1(x). Now,

d/dx cosh^-1(x) = d/dx (-i cos^-1(x))
= -i d/dx cos^-1(x)

But by trigonometry (draw a triangle diagram and use trig identities), d/dx cos^-1(x) = -1/sqrt(1 - x^2). Then d/dx cosh^-1(x) = i/sqrt(1 - x^2), and noting that when |x| >= 1 we have sqrt(1 - x^2) = i sqrt(x^2 - 1), we get d/dx cosh^-1(x) = 1/sqrt(x^2 - 1), |x| >= 1. Done. Complex Analysis FTW.

mikety
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Now when you say "chain rule" it sounds wrong

Gold
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I haven't testet it out, but I have a problem for you:
(f^-1(x))' = (f(x)') ^-1

Leon-nnjq
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Show that cosh^- 1 (1/x) = sec(h ^ - 1) * x

udynkhanikar
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The second method is way cooler, because i don't need to remember anything

perveilov
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find the definite integral of this derivative and youll have a little surprise :D

karinanostan
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I got 1/sinh(arccosh(x)) amirite





Edit: No
Edit again: Yes

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