Inverse hyperbolic cosine [cosh^-1(x)] as a logarithm

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In this video, we find the conventional expression for the inverse hyperbolic cosine function via the definition of hyperbolic cosine.

First, we let the function...

y(x) = cosh^(-1)(x)

Thus...

cosh(y) = 1/2(e^y + e^-y) = x, for which we solve for y.

#Functions #Hyperbolic #Inverse #Cosine

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  1. MasterWuMathematics
  2. Master Wu
  3. mathbff
  4. PatrickJMT
  5. Khan Academy
  6. Mathematics
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Комментарии
Автор

soo both final expressions are correct, but still by convention we use the positive one???

plushiyito
Автор

Fantastice

Few people take one or two tablets

رامحديب
Автор

x = Cos(y), and we all know that cos(y) <1, how could x^2 >1?

quocvu