Determine the position of the particle when t = 4 s

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A particle moves along a straight line such that its
acceleration is a = (4t^2 - 2) m/s^2, where t is in seconds.
When t = 0, the particle is located 2 m to the left of the
origin, and when t = 2 s, it is 20 m to the left of the origin.
Determine the position of the particle when t = 4 s.
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The velocity of a particle which moves along the s - axis is given by v = 2 - 4t + 5 3 / 2, where t is in sec onds and v is in meters per second . Evaluate the position s, velocity v, and acceleration a when t = 3 s . The particle is at the position So = 3 m when t = 0 .

arsheedarsheed-umcd
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Is there a way to do this with definite intergrals

gwuapo
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v= 2t find s at 3 secif at t= 0body is behind origin

sumitpandey