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LeetCode Daily: Convert 1D Array Into 2D Array Solution in Java | September 1, 2024

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🔍 LeetCode Problem of the Day: Convert 1D Array Into 2D Array
In today's LeetCode daily challenge, we solve the problem of converting a 1D array into a 2D array given the dimensions m and n, using Java.
👉 Solution: Pinned on the comments
🌟 Problem Description:
Given a 1D array of integers and two integers m and n, the task is to reshape the 1D array into a 2D array with m rows and n columns. If the reshape is not possible, return an empty 2D array.
🔑 Key Points:
Array Validation: First, we check if the product of m and n equals the length of the original array. If not, the reshape is impossible, and we return an empty array.
Reshaping: The original array is split into subarrays of length n and arranged into the m x n 2D array using the copyOfRange method.
Efficiency: The solution efficiently transforms the array using simple loops and Java’s array utilities.
📝 Code Explanation:
Validation: The code first checks if the reshape is possible by comparing the length of the original array with m * n.
Array Transformation: If valid, it uses a loop to split the array and copy elements into the new 2D array.
Return Result: Finally, the constructed 2D array is returned.
📅 Daily Solutions:
Subscribe and hit the bell icon for daily LeetCode solutions, explained step-by-step!
👥 Join the Community:
Share your thoughts on the problem in the comments.
Discuss different approaches with fellow coders.
If you enjoyed this video, please like, share, and subscribe for more daily coding challenges!
#LeetCode #Coding #Programming #TechInterview #ArrayManipulation #DailyChallenge #Java
In today's LeetCode daily challenge, we solve the problem of converting a 1D array into a 2D array given the dimensions m and n, using Java.
👉 Solution: Pinned on the comments
🌟 Problem Description:
Given a 1D array of integers and two integers m and n, the task is to reshape the 1D array into a 2D array with m rows and n columns. If the reshape is not possible, return an empty 2D array.
🔑 Key Points:
Array Validation: First, we check if the product of m and n equals the length of the original array. If not, the reshape is impossible, and we return an empty array.
Reshaping: The original array is split into subarrays of length n and arranged into the m x n 2D array using the copyOfRange method.
Efficiency: The solution efficiently transforms the array using simple loops and Java’s array utilities.
📝 Code Explanation:
Validation: The code first checks if the reshape is possible by comparing the length of the original array with m * n.
Array Transformation: If valid, it uses a loop to split the array and copy elements into the new 2D array.
Return Result: Finally, the constructed 2D array is returned.
📅 Daily Solutions:
Subscribe and hit the bell icon for daily LeetCode solutions, explained step-by-step!
👥 Join the Community:
Share your thoughts on the problem in the comments.
Discuss different approaches with fellow coders.
If you enjoyed this video, please like, share, and subscribe for more daily coding challenges!
#LeetCode #Coding #Programming #TechInterview #ArrayManipulation #DailyChallenge #Java
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