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Leetcode September Challenge Day 1 2022. Convert 1D array to 2D array
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The main logic to solve this problem is In O(m*n) Time complexity is
Slicing Logic: original[i * n : (i + 1) * n] selects n elements starting from index i * n to (i + 1) * n.
Time Complexity: The time complexity is O(m * n), as each element is processed exactly once.
#dsa #leetcode #coding #programming #education #tamil #python #challenge
Slicing Logic: original[i * n : (i + 1) * n] selects n elements starting from index i * n to (i + 1) * n.
Time Complexity: The time complexity is O(m * n), as each element is processed exactly once.
#dsa #leetcode #coding #programming #education #tamil #python #challenge
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