Integral of 1/(x^6+1) [Very tricky and Difficult Fun Integral]

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Here is another very fun integral:
In this video, I do a very interesting and very challenging Integral. There are many tricky parts but this is a fun integral of 1/x^6+1. This is one of the Most Difficult Calculus Problems.

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My way is the simplest method for calculating this integral,

Int[dx/(x^6+1)]

=1/2*Int[2dx/(x^6+1)]












cemsentin
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If one combines the arctangent terms and natural logarithm terms you'll get:
I = +
+ C.

ernestschoenmakers
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11:30 You know, you could just complete the square. Then the term to replace will be obvious. In this case x² + sqrt(3)x + 1 = (x + sqrt(3)/2)² + 1/4. So substitute u = x + sqrt(3)/2.

nullplan
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Please what about you just do it t this way


Integral (x +1) power -1


And continue with substitution for the x+1 then solve

Will it be accepted as correct?

davidavoryie
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Te confundiste en el signo, en la última integral, debería ir con -1/3

jorgebilicparedesquispe
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You made a mistake right after the partial fraction decomposition. When substituting E and F into the last integral, the negative sign of E was placed in front of the integral and you didn't compensate for that by making the one-third negative.

spaghetti
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Int[dx/(x^6+1)]
=Int[dx/{(x^3)*2+1*2}
=Tan*-1(x*3)+c

It's that right???

pracheekesharwani
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what program do you use to make these vids?

jordanberman
visit shbcf.ru