Mixing Problem Differential Equation (Application)

preview_player
Показать описание
A large tank is initially filled with 100 L of brine (i.e. salt dissolved in water) in which 1 kg of salt is dissolved. Brine containing 1/2 kg of salt per L is pumped into the tank at a rate of 6 L/min. The well-mixed brine is pumped out of the tank at a slower rate of 4 L/min. Assuming that the tank does not overflow, find the amount of salt (in kg) in the
tank after t min (t >= 0).

Looking for help with math? I can help you!
~ For more quick examples, check out the other videos on my youtube channel
Рекомендации по теме
Комментарии
Автор

This problem is done accurately, unlike many examples online where they state the concentration of salt water as number of kilograms of salt per liter of pure water - the volume of water will increase if you add kilograms of salt

maxpercer
Автор

I worked this one out using arbitrary constants and it’s so complicated

theelk
Автор

Why do you. have 2t next to 100, i don't understand where that number come from?

axianaxmerone
Автор

7:17 why the integration of 3(50+t)^2 becomes = (50+t)^3 + C instead of = 7500x+150x^2+x^3+C

aimanjamil
Автор

As t approaches infinite, does the solution in the tank approach the concentration of the liquid going in? If yes, why does the equation point that as t approaches infinite the mass of salt in the container approaches infinite? How is this possible? Thank you in advance

amroalatasi
Автор

Im sorry but i belive this could have been done easily but u have made it more complex

hamzaiqbal
Автор

yung (50 + t)^2x'+2(50 + t)x paano po ba sya naging ((50 + t)^2x)'

JayEulisesAErong