Orthogonal Vectors and Subspaces

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MIT 18.06SC Linear Algebra, Fall 2011
Instructor: David Shirokoff

A teaching assistant works through a problem on orthogonal vectors and subspaces.

License: Creative Commons BY-NC-SA
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I find it's very helpful to have a exercise video after each lecture so you actually know how to solve the problem.
Thank OCW.

phamhongvinh
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I feel grateful that the internet exists. I would never have access to these fantastic lectures. Thank you, MIT!

sheikhshafayat
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Thanks for the help. I personally think you are the best instructor at MIT.

rickshawty
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All of you guys are awesome. I have become fan of this linear algebra tutorial series.

AnupKumar-wked
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God you save my life. I couldn’t go to class in my college because covid and they pass all these in linear algebra and now I understand. Thanks MIT and the profesor

thebreath
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Excellent tutorial! Thank you David and MIT!

supersnowva
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In the 4th and 5th editions of his Intro to Linear Algebra book, Professor Strang includes worked out examples like in these recitation videos in each chapter. It's nice to have a video record nonetheless.

qbtc
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Incidentally, he could've proceeded further with the row reduction to the full RREF to get a matrix of the form [I F] in which I is the identity and F are the free variables. Then, -F would be part of your nullspace solutions directly, ie, your bases for the orthogonal Subspace.

qbtc
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very clear, very concise. Thank you David! Thank you MIT!

quirkyquester
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So why not just use the method Professor Strang taught in class, that to suppose free variable [x3 x4]=I? The answer comes out immediately and you never need to calculate what -2(-a+b)-2a-3b, which is slow, complex and easy to make mistakes.

andersony
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Would it be the same to say that the matrix formed by combining S and S compliment you would have a matrix of rank 4 and therefore can always rewrite a vector of R4 within that space?

benjtheo
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Use the beautiful fact discussed in lecture 14 to solve part 1 "null space and row space are orthogonal complements in R^4 " so null space contains all vectors perpendicular to row space so simply the perpendicular subspcae to A is nullspace of A now just give basis for nullspace of A

bitstsunami
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anyone thought that he has a nice voice? lol

waichingleung
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Wow this is the math knowledge base for control theory to solve coupled differential equations. Am I right?

wuzhenick
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Explanation is good but he could have decomposed the matrix to RREF form from which finding null space if a simple step rather than writing the equations.

balajikalva
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Why he didn't take those vectors into columns?

eduardosdelarosa
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Could S^⊥ be a subspace of c_1[0 -1 1 0]+c_2[-5 1 0 1] ?
It was not specified that it has to be largest space perpendicular to S, so can we also limit ourselves? Or the notation (^⊥) automatically means 'the largest'?

mskiptr
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sure this guy, do like to flex his muscles. 😂 just kidding nyc ques.

iharsh
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This subject in the book is so confusing.

MrSyrian