Integral of 1/(a^2+x^2)^(3/2) (substitution)

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ะŸะพะบะฐะทะฐั‚ัŒ ะพะฟะธัะฐะฝะธะต

โœ… ๐ƒ๐ž๐ซ๐ข๐ฏ๐š๐ญ๐ข๐ฏ๐ž ๐ญ๐จ ๐œ๐ก๐ž๐œ๐ค ๐ญ๐ก๐ž ๐ฌ๐จ๐ฅ๐ฎ๐ญ๐ข๐จ๐ง

๐Ÿ”ง ๐”๐ฌ๐ž๐Ÿ๐ฎ๐ฅ ๐ฏ๐ข๐๐ž๐จs

๐Ÿšถ ๐’๐ญ๐ž๐ฉ๐ฌ
00:00 Substitution: x=a*tan(u)
00:15 Differentiate in both sides
00:23 Substitute x and dx
00:54 Take out a^2 as common factor
01:25 Rewrite expression
01:57 Simplify expression
03:15 Integrate cos(u)
03:23 Undo substitution: u in terms of x
03:54 Use sin(arctan(x)) formula
04:10 Rewrite expression
05:01 Simplify expression
05:08 Add integration constant +C
05:14 Final answer!

๐Ÿ” ๐€๐ซ๐ž ๐ฒ๐จ๐ฎ ๐ฅ๐จ๐จ๐ค๐ข๐ง๐  ๐Ÿ๐จ๐ซ ๐š ๐ฉ๐š๐ซ๐ญ๐ข๐œ๐ฎ๐ฅ๐š๐ซ ๐ข๐ง๐ญ๐ž๐ ๐ซ๐š๐ฅ? ๐…๐ข๐ง๐ ๐ข๐ญ ๐ฐ๐ข๐ญ๐ก ๐ญ๐ก๐ž ๐ข๐ง๐ญ๐ž๐ ๐ซ๐š๐ฅ ๐ฌ๐ž๐š๐ซ๐œ๐ก๐ž๐ซ:

๐ŸŽ“ ๐‡๐š๐ฏ๐ž ๐ฒ๐จ๐ฎ ๐ฃ๐ฎ๐ฌ๐ญ ๐ฅ๐ž๐š๐ซ๐ง๐ž๐ ๐š๐ง ๐ข๐ง๐ญ๐ž๐ ๐ซ๐š๐ญ๐ข๐จ๐ง ๐ฆ๐ž๐ญ๐ก๐จ๐? ๐…๐ข๐ง๐ ๐ž๐š๐ฌ๐ฒ, ๐ฆ๐ž๐๐ข๐ฎ๐ฆ ๐š๐ง๐ ๐ก๐ข๐ ๐ก ๐ฅ๐ž๐ฏ๐ž๐ฅ ๐ž๐ฑ๐š๐ฆ๐ฉ๐ฅ๐ž๐ฌ ๐ก๐ž๐ซ๐ž:

๐Ÿ‘‹ ๐…๐จ๐ฅ๐ฅ๐จ๐ฐ @๐ข๐ง๐ญ๐ž๐ ๐ซ๐š๐ฅ๐ฌ๐Ÿ๐จ๐ซ๐ฒ๐จ๐ฎ ๐Ÿ๐จ๐ซ ๐š ๐๐š๐ข๐ฅ๐ฒ ๐ข๐ง๐ญ๐ž๐ ๐ซ๐š๐ฅ! ๐Ÿ˜‰

๐…๐จ๐ฅ๐ฅ๐จ๐ฐ ๐ˆ๐ง๐ญ๐ž๐ ๐ซ๐š๐ฅ๐ฌ ๐…๐จ๐ซ๐˜๐จ๐ฎ

๐ƒ๐จ๐ง๐š๐ญ๐ž

#integralsforyou #integrals #integrationbysubstitution
ะ ะตะบะพะผะตะฝะดะฐั†ะธะธ ะฟะพ ั‚ะตะผะต
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ะะฒั‚ะพั€

๐Ÿ’ช Thumbs up if you were getting stuck in an electrostatics problem ๐Ÿ˜‰๐Ÿ‘

โœ… ๐ƒ๐ž๐ซ๐ข๐ฏ๐š๐ญ๐ž ๐ญ๐จ ๐œ๐ก๐ž๐œ๐ค ๐ญ๐ก๐ž ๐ฌ๐จ๐ฅ๐ฎ๐ญ๐ข๐จ๐ง


๐Ÿ” ๐€๐ซ๐ž ๐ฒ๐จ๐ฎ ๐ฅ๐จ๐จ๐ค๐ข๐ง๐  ๐Ÿ๐จ๐ซ ๐š ๐ฉ๐š๐ซ๐ญ๐ข๐œ๐ฎ๐ฅ๐š๐ซ ๐ข๐ง๐ญ๐ž๐ ๐ซ๐š๐ฅ? ๐…๐ข๐ง๐ ๐ข๐ญ ๐ฐ๐ข๐ญ๐ก ๐ญ๐ก๐ž ๐ข๐ง๐ญ๐ž๐ ๐ซ๐š๐ฅ ๐ฌ๐ž๐š๐ซ๐œ๐ก๐ž๐ซ:


๐ŸŽ“ ๐‡๐š๐ฏ๐ž ๐ฒ๐จ๐ฎ ๐ฃ๐ฎ๐ฌ๐ญ ๐ฅ๐ž๐š๐ซ๐ง๐ž๐ ๐š๐ง ๐ข๐ง๐ญ๐ž๐ ๐ซ๐š๐ญ๐ข๐จ๐ง ๐ฆ๐ž๐ญ๐ก๐จ๐? ๐…๐ข๐ง๐ ๐ž๐š๐ฌ๐ฒ, ๐ฆ๐ž๐๐ข๐ฎ๐ฆ ๐š๐ง๐ ๐ก๐ข๐ ๐ก ๐ฅ๐ž๐ฏ๐ž๐ฅ ๐ž๐ฑ๐š๐ฆ๐ฉ๐ฅ๐ž๐ฌ ๐ก๐ž๐ซ๐ž:


๐Ÿ‘‹ ๐…๐จ๐ฅ๐ฅ๐จ๐ฐ @๐ข๐ง๐ญ๐ž๐ ๐ซ๐š๐ฅ๐ฌ๐Ÿ๐จ๐ซ๐ฒ๐จ๐ฎ ๐Ÿ๐จ๐ซ ๐š ๐๐š๐ข๐ฅ๐ฒ ๐ข๐ง๐ญ๐ž๐ ๐ซ๐š๐ฅ! ๐Ÿ˜‰

IntegralsForYou
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anyone who came up here while getting stuck at solving electrostatics problems lol

mmukulkhedekar
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WOW! Thanks for doing me a great favor in electromagnetics. Perfect integral performance, from Taiwan.

้™ณๅฝฅ้œ–-pn
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I too was stuck on an electrostatics problem xD

benwinstanleymusic
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Thanks for solving this integral. It helps me in electrodynamics and magnetism a lot. Best wishes from Korolyov, Russia

ะะธะบะธั‚ะฐะะฐะทะฐั€ะพะฒ-ัˆั
ะะฒั‚ะพั€

I'm in an Electromagnetism course now after taking Calc 4 almost 6 years ago. This video gives me faith that I'll be able to make it. Thank you!

jacobthrilby
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For those who got a little bit confused in the beginning (maybe don't remember),
derivative of a.tg(u) is a/cosยฒ(u)du because the derivative of the tangent is the same of the derivative of (sen/cos).
This get us with the quocient rule (sen'.cos -sen.cos')/cosยฒ. This is (cosยฒ+senยฒ)/cosยฒ that is equal to 1/(cosยฒ).

mariaclarascarpellipereira
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Thank you so much buddyโค๏ธ...You saved my day from being stucked up in this integral while doing Electrostatics.

sarathy
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I am grateful to god cuz there are people who reduce our stress considerably and they do not know what they are doing Grateful viewer from India

juverianaeem
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Man, you're awesome.
You're channel is wonderful
The way you solve the integrals is amazing.

garygs
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Could've saved yourself the last three steps by observing that tan(arctan(x/a)) = x/a. Then you get a triangle with opposite side x, adjacent side a and hypotenuse sqrt(x^2 + a^2). The sine of this triangle is opp/hyp = x/sqrt(x^2 + a^2).

W.M.-
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Thanks for this integral. Helped me in electrostatics. Best wishes from India.

adityavenayak
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Thankyou so much.. Now I can solve electrodynamics and magnetism problems easily.. Best wishes from Indianโค

artikuniyal
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Thank You! I wish I could develop the intuition to make that first substitution.

pedromoose
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I love the little vertical equal sign lol

m.espinosa
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It's a very useful video!!! Thanks for it :) (from.KOREA)

DH-sxwd
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Thank you so much. Helped me a lot in electrostatics. Definitely subscribing. Love from India ๐Ÿ˜Š๐Ÿ˜Š

abhirupiitkgp
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Thank you my friend! This type of video Helps a lot

rafaelrosante
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thanks it helped me in electrostat and magnetism ๐Ÿฅฐ

kushmehar
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Thanks so much for posting this! I was wondering how did you get the step you just finished at 4:08?

dianet