Solve for a and b in the Complex Numbers | College Entrance Question | Math Olympiad Training

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Solve for a and b in the Complex Numbers | College Entrance Question | Math Olympiad Training

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[nirupamasingh]

V nice question. V nice explanation. Pl post more questions on complex numbers.

[jayacademydevimandir]

sir your understanding rule is very best campare to other teacher

[tahirmdnumanlaskar]

It was an easy have done it myself.. Alhamdulillah

[fevengr]

Remembered what you said about rationalizing the denominator in previous videos so the solution turned out to be quick and easy. Thanks!

[philipkudrna]

Thank you for also touching complex numbers, even though they practically work like normal algebra. Very interesting!

[thomast.]

I did it a little bit different:
(23 - i) / (2 + 3i) = a + bi | *(2 + 3i)
23 - i = 2a + 3ai + 2bi - 3b = ( 2a - 3b ) + i*( 3a + 2b )
comparing the real and immaginary parts on both sides leads to two simpel equations :
I : 2a - 3b = 23
II : 3a + 2b = -1
2*I + 3*II : 13a = 43 => a = 43/13
a = 43/13 in I : 86/13 - 3b = 23 => b = - 71/13

[anatoliy]

Chic theme of your lesson, sir. I'm just delighted with the complex numbers! It's like a mathematical parallel reality with completely different laws that at first glance contradict common sense, but in fact it is a surprisingly logical world of numbers. In real life, too, there are many people and even entire countries who live in such an imaginary reality, right?Thank you so much, dear Mr Premath God bless you!

[SuperYoonHo]

Very great problem. Thanks a lot.🙏🙏😍🖤🖤

[banazamalsadiwala]

Thank you so much for your best learning video made by u😊😊😊

[susennath]

gradually you r entiring in complex domain.

ok

good sign.

but how much potential can be effort our audience that should be followed.

[Viesto]

The "i" is imaginary unit. "bi" is imaginary number. Complex number has two parts - the real part and the imaginary part. "a" is a real number and a real part of complex number, and bi is imaginary number and an imaginary part of the complex number. Greetings!

[Praveen_]

I know this question how to solve being a 10th class student 🔥

[mehulpunia]

(x-3)(x-4)=34/1089 solve for x.Solve it if you are a mathematician

[robertcotton]

We never got told a and b real so last step can't be assumed infinite solutions allowing them be complex

[hanzalakhan]

Sir, plzz keep dark theme in your video for eye comfort.

[Teamstudy]

2nd comment and ans is a = 45 and. b = - 25

[부계정-xbi]

yeah I always use (x-y)(x+y) and it works here too