Java String interview Questions and Answers with example| Immutable | Most Asked | Code Decode

In this video of code decode i.e. Java String Interview Questions and Answers for freshers and experienced.

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We have taken some most commonly asked Interview questions along with their answers

This string Interview questions are asked in almost every interview of Java whether it would be freshers java interview or experienced java interview

Please watch this video of Most Asked String Interview Question as it cover very important string interview questions and answers.

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What are the different ways to create string objects?

String objects can be created in two ways:

Using the ‘new’ operator.
Using double-quotes.

String S1 = new String("code");

String S2 = "decode";
When the String is created with the double quotes, JVM searches it for in the string pool; if the same value is found, it returns the reference to that String else creates a new object with the new value provided.

In the other case, if the String is created with the ‘new’ operator, then JVM creates a new object but not in the string pool. If we want to create the object in the string pool, we can use the intern() method.

What is a string constant pool?

The memory space allocated in the heap memory to store the string literals is called the string constant pool.

No two string objects can have the same value in a string constant pool.

Why is Java provided with String constant pool as we can store the objects in heap memory?

String constant pool provides the facility of reusability of the existing string objects.

When a new string object is created using the string literals, then JVM first checks in the pool if this String already exists or not.

If it exists, then it will reference the existing String rather than creating a new object.

This will help in the speeding up of the application and also helps in saving the memory as no two objects will have the same content.

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[Sunilkumar-jnci]

Very Well explained !.


Just want to add for last example, when you do concatenation of s1 + "decode" , it actually creates a new object for "decode" and than "CodeDecode", after the 2nd line there will be 3 objects in string pool.

Thanks for reading, correct me if you think differently.

[manishagarwal]

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[suyashgupta]

please cover the most asked string coding interview questions.
Your content is awesome!!
Thanks for the hardwork

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[harshsanmukhani]

Your concepts are very clear.. You are making really great videos for everyone. Pls do make the video on string coding questions as well. I want to suggest one example as well which i have been asked in my interview. I had to replace the vowel with the number of occurrences let me explain with example... Suppose there is a string as opportunity so i have to replace o with 2, u with 1 and i with 1 as well because, as you can see that the vowel has been replaced with the number of occurrence, i was also asked to iterate an string using map for this logic.

These type of questions can also clear many concepts and help to think big and build the logical thinking. I belive you will be making a video on that as well with great examples.

Thanks for making such a great content for everyone. Really appreciated. 😄😄🙌

[gautamagarwal]

Excellent video! Just to the point and lots of important learnings to take away from this video! 👍👍

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This is really really helpful. Got all my doubts cleared related to Strings in java with this one.

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Please add string programming interview qwestions also..

[nagapradeepvankayala]

Excellently covered end to end complete string concept...

[firdousbelim]

Very very Nice Explanation mam. Please make series of java interview questions
Array. Loops. Oop and collection framwork.

[testingvinod]

One que: if unattended 'code' created while creating obj then what is the use of unattended 'code' where we can use ?

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