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[rohitkasture]

String reversal is not space efficient, everytime a new string object will be created whenever we append the result

[ronakparjapati]

If original array contains same more than 2 remove elements....???? Sorry sir but this code not work properly in every scenario

[sivasankarkuna]

boolean isPalindorme(String str ) {
for (int i = 0; i < str.length()/2; i++) {
if (str.charAt(i) != && i!=str.length()/2) {
return false;
}
}
return true;
}

[manasanayak]

The value while debugging at 48s showed wrong because by mistake you had modified code and it was not saved after changing back

[shikhasoni]

In palindrome check, you've used empty string, since strings are immutable it is inefficient code, we can use stringBuffer instead

[amolpatil]

Finding Non repeted chars from string best approach:

public static void main(String[] args) {
String s = "aaabbbccdee";
char[] array = s.toCharArray();
for(int i = 0;i<s.length();i++) {
char temp = array[i];
int count = 1;

for(int j =i+1;j<s.length();j++) {
if(array[i]==array[j]) {


}
}
if(count==1) {

break;
}

}

}

[rachamallidorasrivignesh]

Sir i am not getting the output for non repeated charecter in string program could you send the code for me

[sainath]

public class Program
{
static void Main(string[] args)
{
string str = "aabbdef";
var result = from obj in str
group obj by obj.ToString()
into egroup
select new
{
uniqueChar = egroup,
count = egroup.Count()
};
foreach(var res in result)
{
if(res.count == 1)
{
= "+res.uniqueChar.Key + " " + "count = "+ res.count );
break;
}
}
}
}

[PrashanthArjun]

In first program sandeep output gives sandep how the 'e' removed

[sivasankarkuna]

// abcdaebc // Non repeated first character
char nonReapeatedFirstChar(char[] str, int index) {
char c = str[index];
int count = 0;
for (int i=0;i<str.length;i++) {
if (c==str[i]) {
count++;
if (count>1) {

nonReapeatedFirstChar(str, index);

}
}
}
return c;
}

[xbpfrym]

removeDuplicateString

void removeDuplicateString(String s) {
String duplicateRemoved="";
for (int i = 0; i <s.length() ; i++) {
if

}
}

}

[sohaibelbokhari]

JAVA 11
static String eliminerDoublons(String mot) {

String motsTraite = mot.chars()
.mapToObj(c -> String.valueOf((char) c))
.distinct()


return motsTraite;
}