How to Crack The Ramanujan Radical Challenge

preview_player
Показать описание
Hello My dear family I hope you all are well if you like this video about "How to Crack The Ramanujan Radical Challenge" for Math Olympiad Preparation then please do subscribe our channel for more mathematical adventures like this.

Are you ready to tackle the Ramanujan Radical Challenge on de-nesting nested radicals? Join us as we delve into this intriguing puzzle and uncover strategies to crack it! Whether you're a math enthusiast or just love a good brain teaser, this video is for you. Let's unlock the secrets behind Ramanujan's radical equations together!"

Topics Covered:
1. Understanding the basics of radical equations using Ramanujan's approach
2. Analyzing the de-nesting of the given equation.
3. Step-by-step approach to solving the radical equation.
4. Tips and tricks for handling tricky radical system of equations like a pro.
5. Algebraic identities and manipulations while solving equations.

Timestamps:
0:00 Introduction
0:44 De-nesting nested radical
1:15 Algebraic manipulations
3:04 Solving system of equation
7:20 Evaluating x
8:53 Answer

#ramanujan #mathpuzzle #radicalequations #mathematics #problem-solving #challenge #education #math #puzzle #strategy #algebra

🎯 This video is perfect for students, math enthusiasts, or anyone seeking to sharpen their problem-solving skills and gain confidence in dealing with radical equations. 🎓📈

🔔 Challenge yourself and see if you can solve the equation before we do! Hit the like button if you're up for the challenge and remember to subscribe for more exhilarating math content! 🛎️🔔

Don't forget to like, comment, and subscribe to join our math-loving community. Let's get started on this exciting journey together! 🤝🌟

Thanks for Watching!
@infyGyan
Рекомендации по теме
Комментарии
Автор

...thanks for sharing...it was a wonderful explanation....x=3

mohammedsaysrashid
Автор

Thanks a lot for your interesting and joyful solutions ^.^

woobjun
Автор

A tiny version.

Take √3 common in 1st term of l.h.s. gives

√3(5+ 2 .√3 .√2 ) i.e
√3 (√3+√2)^2
Removing root gives eqn
3^1/4 ( √3+√2) - 3^1/4 .√2= x^3/ 4 i.e
3^ 3/ 4= x ^3/ 4
Gives x = 3

Ramanujam will happy to see .

Quest
Автор

Very clever.
Why is this Ramanujan's. It seems too simple for someone of his caliber!

roberttelarket