Related Rates: Tracking a Rising Hot Air Balloon

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This is Eric Hutchinson from the College of Southern Nevada. Thank you so much for watching!

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Hello! Great video, just a quick question:

Since we have a 45 degree angle, can't we use cos(θ) to calculate the hypotenuse (at that moment)?

cos(θ(t0))=adjacent (t0)/hypotenuse (t0)

cos(45)=500/h
h= 1000/√2 ft

then using sin(θ)=opposite(t0)/hyp(t0)

op(t0)=sin(θ)*1000/√2

op(t0)'=1000/√2*cos(θ)*θ'=
1000/2*0.14=70ft/min

What am I missing here? Thanks in advance 😊

OrestesPapanastassiou
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Sir how is 2 the value of Sec pi by 4 pls reply

dr.abhasingh
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When it was tan(theta) = y/500, I actually put the value of tan45 and couldn't move forward. Thanks

BadBoy-wyil
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Dude looks like John Green after a mid-life crisis

Michael-qitw