Use MI to prove 1²+3²+5²+....+(2n-1)²=n(2n-1)(2n+1)/3 Part-2

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Use MI to 0:06:37

Use MI to prove 1²+3²+5²+....+(2n-1)²=n(2n-1)(2n+1)/3 Part-2

Prove the following 0:11:03

Prove the following by the principle of induction | 1^2 + 3^2 + 5^2 +…..+ (2n-1)^2 = n(2n-1)(2n+1)/3...

2.v) 1²+3²+5²+....+(2n–1)²=n(2n–1)(2n+1)/3 Using 0:09:20

2.v) 1²+3²+5²+....+(2n–1)²=n(2n–1)(2n+1)/3 Using principle of mathematical induction show for all n....

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Mahesh Bhattarai // 0:16:37

Mahesh Bhattarai // Math 11// Mathematical induction//1^2+3^2+5^2+ .... + (2n-1)^2 = n(2n-1)(2n+1)/3

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By using MI prove that 1²+2²+3²+....+n²=(n(n+1)(2n+1))/6

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1/1.3+1/3.5+1/5.7+...+1/(2n-1)(2n+1)=n/2n+1 0:07:11

1/1.3+1/3.5+1/5.7+...+1/(2n-1)(2n+1)=n/2n+1

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Prove by the principle of induction for all n belongs to N | 1^2 + 2^2 +...+ n^2 = n(n+1)(2n+1)/6

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prove that 1² + 2² +3²........+ n²= n(n+1)(2n+1)÷6 || or sigma n² = n(n+1)(n+2)÷6 ||

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Prove by mathematical Induction the formula: 1^2 + 2^2 + 3^2 + ... + n^2 = n(n+1)(2n+1)/6.

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