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Circular Particle Motion | Changing Acceleration | Dynamics
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Welcome to Engineering Hack! In today's video we go over a problem in which the acceleration is not constant, meaning we need to integrate its general equation to find the acceleration we're being asked. Its a problem around circular motion, so remember that we'll have two components for the acceleration (Problem 12.137).
Problem statement: A particle travels around a circular path having a radius of 50 m. If it is initially traveling with a speed of 10 m/s and its speed then increases at a rate of v̇ = (0.05 v) m/s², determine the magnitude of the particle’s acceleration four seconds later.
Answer:
Magnitude of acceleration = 3.06 m/s²
To learn more please watch the video till end and if you have a question just ask in the comments section.
If you like the video, please SUBSCRIBE and don't forget to press the bell 🔔, 👍like, comment and share. ---------------------------
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#dynamics #EngineeringHack #circularmotion #twodimensional #engineeringsolutions #engineeringaustralia #engineering #KinematicsofParticles #Kinematics #changingacceleration
Problem statement: A particle travels around a circular path having a radius of 50 m. If it is initially traveling with a speed of 10 m/s and its speed then increases at a rate of v̇ = (0.05 v) m/s², determine the magnitude of the particle’s acceleration four seconds later.
Answer:
Magnitude of acceleration = 3.06 m/s²
To learn more please watch the video till end and if you have a question just ask in the comments section.
If you like the video, please SUBSCRIBE and don't forget to press the bell 🔔, 👍like, comment and share. ---------------------------
---------------------------
▶️Watch More Videos:
---------------------------
#dynamics #EngineeringHack #circularmotion #twodimensional #engineeringsolutions #engineeringaustralia #engineering #KinematicsofParticles #Kinematics #changingacceleration