solve these jee mains questions in seconds #jee2023 #jeemains2023 jeem #jeemains #iit #jeemotivation

[sanjaypoddar]

Bro took the most easy ques of jee mains😂😂

[AlstonDsouza-jlow]

2, draw modulus and cosine function within the closed interval [-1, 1] will give u two solutions

[naveenpatil]

First squaring on both sides then cos² x = 1- sin²x then send 1 the other side then from the interval of sin x put them in the equation you will get 0 and 1 so two solutions.

[komalmalik]

Mod hatao + - lagao simple x=+ - cosx
No. Of solution=2

[prabhatgupta]

indeed this graphical method is super cool and easy but I thought it in another way please let me know if I'm right: |x|=cosx
cosx > 0
cosx is positive only in 1st and 4th quadrant
x = cosx where x belongs to 1st or 4th quadrant
thus, for same x there will be two angles (value x) each in 1st and 4th qd


So, 2 solutions

[BTOXIC]

One more important conclusion is that where graph of two functions intersect coordinates are equal .... It is simple observation but in pressure students can't even spot this...😅

[Crazy_mathematics]

Graphing method will help it => ans is "2"

[MasteringProductivity]

Just take x= cosx and x=-cosx=> x=cos(pi-x) number of solurion 2

[AvinashKumar-tovh]

Mene kabhi bhi jee nahi diya but fir bhi me jee ke questions solve kar leta hu.

[LearnwithME]

no. of soln. 2, by compare it's Range. only one 0 and 1

[Yashu.cv_rks]

Bro aisa ques schme ata ha kya like mera dekte hi hogya tha toh schme ata ha ye jee mains me?

[gytricky]

2 simple make graph and find intersection

[bharatsoyal]

Bhaiya one doubt is:
How to fill numerical in jee mains suppose 6 box hai or mera ans. 5 aya to vo 6 box me last box me 5 likhna hota hai ya 1st box plzzz reply

[vishalsingh]

I think Jo serious aspirant h use ye pata hoga

[supernova]

cs0=1
cos120=-1
Therefore, 2 solution

[madeshvaithya]

Square on both sides then 2 on the power of x

[eddy]

Bro took the easiest question to show off his skill😂

[HopefulPassengerShip-yorp]

Cos x axis is 0 because it is present in center graphical

[BhargavGorru]

In place of that qution, polynomials are present
Then how to find sir,
I though that to find roots . Roots solutions right sir

[SanjanNath-quit]

We can use the range of cosx (-1<=cosx<=1).as we use modules then there will be only two solutions -0 and 1.
I think it's quite easier than the intersection of graphs method.