LDR and LED Circuit design - Solid State Relay

How to make a simple solid state relay using an LED, a LDR and resistor. Shown with calculations.

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[EngineeringMindset]

⚠️ *These videos take a long time to make* if you would like to buy Paul a coffee to say thanks, link below: ☕

[amitp]

I liked the practical demonstration along with the animations.
Thankyou

[jhana.]

The best explanation of LDR I've ever seen on YT. Showed everything about him. It left nothing to be said. Thanks for the perfect job !

[AhmedOsman-syjg]

While i was looking for videos to learn electricity i never find better than paul 80% of my electric basic informations is from him i will remain thankful and supporter

[TopGPilot]

Always something interesting to learn from you, I swear lol

[mybrainlearningchannel]

The first thing came into my mind on LDR is long distance relationship.... By the way Sir, this is the best channel I've been watching since I started working in building facilities... I consider this channel as the most informative video tutorial channel when comes to building equipment and other devices....

[JjMn]

Very cool! Very informative design on how an optocoupler works.

[MrLee-cypw]

You sir are a blessing to the internet.

[NickElectronics]

It is worth mention applications of LDR.
Camera light meters, clock radios, alarm devices (as the detector for a light beam), nightlights, outdoor clocks, solar street lamps, and solar road studs.

Photoresistors can be placed in streetlights to control when the light is on.
Thanks!)

[afrosaratoga]

This is very interesting. I didnt know what a LDR was until today but the example you've shown reminded of me how Optoisolators works. Useful to protect expensive equipment in case of a Overload on the output side.

[АлексейКуракин-эп]

Thank you for explaining and showing animations, I'm delighted😉👍👍

[jhana.]

Your videos are very...very...very good!

[okithdesilva]

Hey Paul thankyou so much for this video

[danielbarbosa]

2:40 What I believe is the correct way of calculating the necessary resistor to implement in our circuit; we should first determine what is the voltage drop across the 70 Ohm LDR, first:

[LDR] V = R x I = 70(Ω) x 0.02(A)
<=> [LDR] V = 1.14(V).


Now that we have found what the voltage drop around the LDR is, we can calculate the voltage drop that needs to take place in the Resistor we are trying to find. We subtract all the voltage drops from the original 9(V) battery:


[Voltage drop from the required Resistor] R(V) = [Battery/Total] 9(V) - [LED] 2(V) - [LDR] 1.14(V) = 6.86(V)


Now that we now that our Resistance will give us a 6.86(V) drop after we implement it; we can calculate what actual resistance (in Ohm) it will consist of:

R(Ω) = 1.14 (V) / 0.02 (A) <=>

R = 343 Ω.


Am I correct, or am I missing something?

[digimon]

Interesting. Im into cars and have been installing and conceptualizing all sorts of security measures into 90s/older cars (chips, rfid, etc). Would be interesting to use a light based "key" in a security system bc we dont usually associated a light as a "key". Or use it for just 1 part of security system.

[fabianmof]

Better to be a loyal audience than the first audience. 👍👍👍👍👍.

[Doitcreative]

Wow
Really thanks for explain the ohm's law i really understand easily
Thanks one's again🙏🤤😄

[sibashishmishra]

I m very much enthusiastic about engineering . So I made a bench type drilling and screwing manual machine..

[mohammedalshrief]

Very accurate machine learning iron station watch it and see how difference science integrate💝💝💝

[circadevices]

You wouldn't happen to know which LDR you were using? These values are exactly what I'm looking for. Thanks!