Product Rule With 3 Functions - Derivatives | Calculus

This calculus video tutorial explains how to find the derivative of a problem with three functions multiplied together using the triple product rule.

Equation of the Tangent Line:

Simplifying Derivatives:

Derivatives - The Product Rule - f*g:

Derivatives - Triple Product Rule - f*g*h:

Derivatives - Quadruple Product Rule - f*g*h*k:

___________________________________
Derivatives - The Quotient Rule:

Derivatives - The Chain Rule:

Chain Rule With Trig Functions:

Chain Rule - Harder Examples:

Chain Rule - Triple SQRT(x):

_________________________________
Derivatives - Composite Functions:

Implicit Differentiation:

Derivatives - Inverse Trig Functions:

Derivatives - Exponential Functions:

Derivatives - Logarithmic Functions:

___________________________________
Final Exams and Video Playlists:

Full-Length Videos and Worksheets:

Derivatives - Formula Sheet:

[chiisanakyojin]

refreshers for derivatives, you’re one of the YouTubers who’ve helped me. Thank you

[OscarDarko-jd]

U're a real helper, I wish u would sit in ur class one day🙏🏽👏🏽👏🏽👏🏽👏🏽

[mowafkmha]

i love you bro you save my life every day when i find my self stuck every time i search on youtupe and always find you first big respect for you the fear of math is gone

[MathZeimer]

My question would be whether this pattern could be applied to the product rule with however many functions.

[jxtxun]

I never learned this in calc 1! thanks! Just finished calc 4 and need to pick up all other skills I may not know about. :)

[almewai]

Thank God you were born to save us ♥️♥️🙏🙏

[nathaliarodriguez]

I’m learning this right know. Thank you for the extra help! ☺️

[georgesadler]

Professor Organic Chemistry Tutor, thank you for a short analysis of the Product Rule With Three Functions in Calculus One. This is an error free video/lecture on YouTube TV with the Organic Chemistry Tutor.

[Alkimachos]

bro... this is so much easier than whatever the fuck my teacher was doing


wtf

[MusaYusuf-wmfy]

U so great legend sir tnx for ur patronage.

[australianmagpie]

Honestly, we didn’t cover this in class, but it’s a little bit self-explanatory, so I managed to solve it ?)

Idk, you can visualize it as a diagram, in which you have a product rule inside another product rule. You grab the first two terms and apply the product rule. Then (after derivating them, you kind of synthesize them into a new term and apply the second product rule. Something like this:
v= x^2 (sinx) v’= x^2(cosx)+(sinx)(2x)
u= In(x) u’= 1/x
f’(x)= vu’+uv’= (x^2 sinx)(1/x)+ In(x)( x^2(cosx)+(sinx)(2x)) =

[Karim-nqbe]

It's easier to get this using associativity and induction : (ABC)' is just (A(BC))' and then just use the derivative rule for two functions f and g where f = A and g = BC.