Solve Linear Trigonometric Equation sin(x/2)=1 (a) for all solutions, and (b) over interval [0,2pi)

The trigonometric equation to be solved is sin(x/2)=1. The unit circle is used to find values for (x/2) in the interval [0, 2pi). The period of the sine function is 2*pi, so 2pi*n, where n is an element of the integers, is added to the solution found on the unit circle. Then all degree solutions for x are found by multiplying this solution by 2. Finally the solutions in the interval [0, 2pi) are found by substituting values for n into the equation found for all radian solutions.

Timestamps
0:00 Introduction
0:55 Unit Circle
1:46 (a) All Radian Solutions
2:55 (b) Solutions in [0,2pi)