Majority Element - Leetcode 169 - Hashmaps & Sets (Python)

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Комментарии
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Master Data Structures & Algorithms For FREE at AlgoMap.io!

GregHogg
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I follow neetcode, but not every explanation of his understandable for me, but your is defferent. Your explanation is awesome. Great Greatt !!!!

moein
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Hi, thanks for the video. The solution is not working with such array [2, 2, 1, 3, 3, 2, 3, 2, 3, 1, 1, 1, 1, 2, 2], so I assume that the variant with HashSet is better in this case.
Thanks.

artemborysenko
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h = Counter(nums)
return max(h, key = h.get)

Channel_SPS
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The majority elements count cant be reduced completely by any other elements count and finally the majority element will be having enough count to be in the ans variable even after checking all other elements

Fastforwardj
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why did you give it a Difficulty score of 8 in algomap

mamineamin
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This is an implementation of Kadane's Algorithm right?

mbe
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count = collections.Counter(nums)
majority_ele = max(count.values())

for n in nums:
if count[n] == majority_ele:
return n
can we do this i did this and leetcode accepted the solution

vidhansaini
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Calling it "count" in the second example is misleading. Its more like a weight or something like that. :D

Blafasel
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wtf lol why is this working, and who the heck came up with this confusing but smart solution

hamids