In Fig. 6.19, DE || AC and DF || AE. Prove that BF/FE = BE/EC.

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In Fig. 6.19, DE || AC and DF || AE. Prove that BF/FE = BE/EC.

In Fig. 6.19, DE is parallel to AC and DF is parallel to AE. Prove that BF/FE = BE/EC.
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u need some powerfull and energetic voice##

davisgamerz
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Tq soo much sir u made the sum to understand so easily so.tomorrow is my exam I will definitely get full marks from these question

VenkataravanappaveVenkataravan
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Kaash aise questions board mein bhi aaj jaayein.

LinaSaroj
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Thank you so much sir because this came to mid term exam🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻

LilavathammaLilavathi
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Thank you so much sir for explaining it in a very well order!!!

L.Sbeats
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Thank you so so so so so so much sir because this has came to mid term exam

Doddabhyraiah.B
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Sir if I write
DE //AE , implies AD/DB = BE/EC
DF //AE, implies AD/DB =BF/FE....(2)
From 1 and 2
BE/EC =BF /FE
Sir is this correct?

pavanashreeng
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Thoda josh cahiye sir bilkul aag jaise

puneethrs