[Discrete Mathematics] Truth Tables Examples

preview_player
Показать описание
We do some practice questions with truth tables to find logical equivalence.

LIKE AND SHARE THE VIDEO IF IT HELPED!

*--Playlists--*

*--Recommended Textbooks--*

In this video we use truth tables to prove tautologies and contingencies.

Hello, welcome to TheTrevTutor. I'm here to help you learn your college courses in an easy, efficient manner. If you like what you see, feel free to subscribe and follow me for updates. If you have any questions, leave them below. I try to answer as many questions as possible. If something isn't quite clear or needs more explanation, I can easily make additional videos to satisfy your need for knowledge and understanding.
Рекомендации по теме
Комментарии
Автор


It comes with video lectures, text lectures, practice problems, solutions, and a practice final exam!

Trevtutor
Автор

I've just found this "classes". Soooo helpful for me to get the basics of discrete mathematics! Thank you!

annalindborg
Автор

I’ve been struggling so hard with this stuff but u make it look so easy omg ur brilliant

akywongster
Автор

thanks very much, i never understood these stuffs in class. love you so much Trev

KambeleChatroom
Автор

I wish I had a question 😂♥️ but thanks a lot for high quality teaching.

ossahmadrezaazimikohnabi
Автор

2:31 Pretty sure the fourth row is supposed to be false ( 0 —> 1 )

HDitzzDH
Автор

[( A → B ) ∧ A] → B is a tautology

However, instead of [( A → B ) ∧ A] we can not take B, isn't it?
I mean [( A → B ) ∧ A] is not the same as B, isn't it? @03:16 to 03:23

eimaldorani
Автор

About 2:12
Guys, k->j = 1 if and only if k<=j

LR-wfoq
Автор

Why is: 'not P' = 1 + 'not(p or not q)= 0 in the 'Conditional' not = 0?

briananderson
Автор

is there an easy way to solve these problems without drawing out a truth table that i should know at this point, or is it normal do make truth tables for all of these problems

mikaelsag
Автор

you have stated in a previous video, that if a p=1 and q=0 in a conditional then p--->q = 0, yet here u put a 1, im i wrong???

karimalrawas
Автор

3:05 You say you're simplifying. I would've thought [-(p || -q)->-p] would simplify to [(-p || q)->-p], but you say it simplifies to [(-p && q)->-p]. Can you explain why this is the case? Am I missing something?

liloupalomino
Автор

i love this playlist buh can you recommend like a site or a book where I can get more activities

jonakatin
Автор

why is 2:31 true ? Shouldn't it be false ?

fancyAlex
Автор

Please what of word problems on this topic

shegetsitdone
Автор

If I study Hard -- then I will pass == Satisfied with result :)
If I study Hard -- then I don't pass == not satisfied with result :(
If I don't study hard -- then I pass == F**k Yeah I am satisfied :D
I I don't study hard -- then I don't pass == F**k it, I didn't study so I am satisfied with results :)

i found this comment on another youtube video and it explains if then truth table. Hopefully this helps. If this is wrong let me know.

sulemanahmed
Автор

`~(p v~q)--> ~p can you explain more better cos i don't get the logic

johnfred
Автор

You are putting 1 0 on the P column but our teacher is putting 0 1 on the P column. What should I put?
i.e
P
1
0
Our teacher:
P
0
1
I have learned that these are the binary equivalent of 0 and 1 and so on. i.e binary of 0 is 0 and binary of 1 is 1. So the first column starts from 0 and so on. So we should put first 0 then 1. Why are you doing the positive?

Mahanmarwat
Автор

admin ... can you explain the meaning of arrow ???

selvakumar-vdoy
Автор

for biconditionals the rule u said was "when am I lying to u, so for not(p v not q) for last one its like one is true and the other is false why is it true then. Its like u didn't put sunscreen but it was sunny or vice versa, either way on one side u r lying

neharikapuri