Evaluate: lim(x →0) (xe^x - log(1 + x))/x2

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Evaluate: lim (x→0) (xex – log(1 + x))/x2

lim x to 0 sinx/x =1

proof

#limitandderivative
#calculus

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  1. Seekho aur sikhao
  2. lim(x →0) (xe^x - log(1 x))/x2
  3. lim(x to 0)(xe^x-log(1 x))/x^2
  4. Evaluate: lim (x→0) ((xex – log(1 x))/x2)
  5. Evaluate lim (x→0) (x e^x -log(1 x)) / x^2
  6. limit x approch to 0
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