filmov
tv
Evaluate `int_(1/3)^1 (x-x^3)^(1/3)/x^4dx`
Показать описание
Evaluate `int_(1/3)^1 (x-x^3)^(1/3)/x^4dx`
Doubtnut
Рекомендации по теме
0:04:19
Evaluate `int_(1/3)^1 (x-x^3)^(1/3)/x^4dx`
0:03:44
The value of the integral `int_(1//3)^(1)((x-x^(3))^(1//3))/(x^(4))dx` is
0:01:47
IIT JEE INTEGRALS Evaluate: `int((x-x^3)^(1/3))/(x^4)dx`
0:07:34
integrate (x+x^3)^1/3/x^4 | integral (x plus x cube) ka whole power 1/3 upon x power 4 |
0:41:07
Integration By Partial Fractions
0:02:08
IIT JEE INTEGRALS Evaluate: `int1/([(x-1)^3(x+2)^5]^(1/4))dx`
0:08:33
You're gonna love this satisfying integration problem (integral from zero to infinity of 1/(x^4...
0:03:44
Evaluate definite integral (x^2 sqrt(x^3 +1)) dx over [0, 2] using method of substitution
0:11:34
∫1/(7x-5)^2+1/√ 5x-4dx, ∫1/(2-3x)+1/√3x-2dx #Integrations L353
0:11:16
Integrating Exponential Functions By Substitution - Antiderivatives - Calculus
0:02:24
IIT JEE INTEGRALS Evaluate: `int(dx)/(x^(1/2)+x^(1/3))`
0:03:29
Integral of x/(1 + x^4)
0:03:35
The value of integral ∫_0^2〖(8-x^3 )^(-1/3) dx〗 in terms of Beta function is:(a) 1/3 B(1/3,2/3)...
0:02:10
Integration By Substitution Problem#2. ∫ (x³+2x)⁵ (6x²+4) dx
0:22:40
What Integration Technique Should I Use? (trig sub, u sub, DI method, partial fractions) calculus 2
0:08:05
Evaluate the Integral (x^3 -2x^2 + x +1)/(x^4 + 5x^2 +4) dx. Partial Fraction Decomposition
0:03:30
`int(dx)/((x+1)^(3/4)(x-2)^(5/4))` 5/4
0:06:53
Integral Practice #4: integral of (x^3)(sqrt(x^2 + 1)) (MIT integration bee 2016 qualifying round)
0:01:37
Integral of (2x+3)^4 using 'Integration by Substitution' - Complete Walkthrough
0:01:40
integrate x(1-x^2)/1+x^4 dx
0:02:09
Integral of 1/(2x-3)
0:10:06
Evaluation of Improper Integrals by Contour Integration
0:05:36
Evaluate the definite integral over [0,1] r^3/(sqrt(4 + r^2)) dr Integration by Parts example 24
0:03:26
IIT JEE INTEGRALS If `y=intsqrt(x)(1+x^(1/3))^4dx'i se q u a lto'`