Don't Slip that Block! Calculate Force (max horizontal) using static friction

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Two identical blocks 1 kg are stacked one on top of the other. The bottom block is free to slide on a frictionless surface. The coefficient of static friction between the blocks is 0.35.What is the maximum horizontal force that can be applied to the lower block without the upper block slipping?
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I find it utterly insane how simple this problem is. Can't believe I had gotten it wrong. Thanks :)

ironphan
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Why is Fn found by adding the two blocks masses when the friction is between the two blocks? Shouldn't Fn account for the force of block 1 on block 2?

elyssahaup
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(F - f )acts on lower block, and f acts on upper block . For without slipping both have to move with same acceleration thus their masses are equal, F- f= f, F= 2f = 2umg

kpraveenkumarkpraveenkumar
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I say 9.6 at 1:44 but I mean 19.6 as it is written

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