Speed, Distance & Time - Shortcuts & Tricks for Placement Tests, Job Interviews & Exams

Crack the quantitative aptitude section of Placement Test or Job Interview at any company with shortcuts & tricks on Speed, Distance & Time. Extremely helpful to crack entrance exams like MBA, Banking – IBPS, SBI, UPSC, SSC, Railways etc.

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0:00 Quantitative Aptitude
0:46 FORMULA
5:21 A boy increases his speed to 9/5 times of his original speed. By this he reaches his school 30 minutes before the usual time. How much time does he takes usually?
8:32 Ramesh sees a thief at a distance of 80 m. Ramesh starts chasing the thief who is running at a speed of 5 m/s. Ramesh is chasing him with a speed of 7 m/s. How much distance does the thief cover before Ramesh catches him?
12:47 P, Q and Rare in a cycle race of 4500 meters. P cycles twice as fast as Q. R cycles 1/3rd as fast as Q. R completes the race in 45
15:52 Ajay and Vijay travel from A to B at 17 km/hr and 19 km/hr, respectively. A is 72km away from B. Vijay reaches B first and returns immediately and meets Ajay at C. Find B to C distance?
19:22 Surendra travels from home to office by car. With an average speed of 50 km/hr, he is late by 30 minutes. But when he comes with a speed of 60 km/h, he reaches his office 10 minutes earlier.
24:49 Rohit drives from his home at a speed of 30 km/hr and reaches his bank 20 minutes late. Then the next day he increases his speed by 15 km/hr but still he is late by 8 minutes. How far is his bank from his home?
27:01 Pratik travels 96 kms at a speed of 16 km/hr using a bike, 124 kms at 31 km/h by car and another 105 kms at 7 km/h in horse cart. Then, find his average speed for the entire distance travelled?
30:17 Rohit covers one-fourth of the total distance at 20 km/hr, one- fourth at 10 km/h and rest of his journey at 80 km/h. Find Rohit's average speed for the whole distance?
33:47 A walks from Jammu to Delhi and at the same time B starts walking from Delhi to Jammu. After passing each other, they complete their journeys in 361 hours and 289 hours, respectively.
37:13 A car travelling with 5/7th of its actual speed covers 42km in 1hr. 40mins. 48 secs. Find the actual speed of the car.

[Anabelle]

I used to hate this concept because most people who teach this directly go to “speed ratio is x:y, so time ratio is y:x. … y-x is N units. Equate this to this and that to that.. done! Option so and so is the answer.. this is how we solve it without using a pen and paper”.. Sometimes they even say “if you take more than 30 seconds to solve this, you’re a waste, you’re a loser” lol!
It makes you feel dumb, as if you can never solve these problems. But this video made me feel at ease. Even the tone and voice modulation of the teacher matters. It makes you feel anxious or comfortable. This teacher’s voice is soothing and his tone is good too. He is also saying things like “see how easy it is?”.. it gives you confidence! Thank you, sir, whoever you are! ❤

[pakkul]

After spending 20 years in software, I was curious to solve aptitude problems again. No teacher used to explain them with such clarity as it is explained here. I am glad to solve them. Thank you!!

[pamapam]

Good Efforts.

Aside for students :
Let A and B are two variables such that product is always constant.

Using the concept of inverse proportions we have --

1. If A increases by x/y then B will decrease by x/(y + x)
2. If A decrease by x/y then B will increase by x/(y - x).

These two relations will solve ANY problem where product of two variables is constant.

Example 1 : If speed increase from 40 kmph to 50 kmph, it means speed increase by 10 kmph or 10/40 = 1/4th. Here time will decrease by 1/(4 + 1) or 1/5th. If we know the decrease in time, we can find the original time. In this example if we say initially boy reaches school 10 minutes late @ 40kmph but reach 20 minutes early travelling @ 50kmph, then time decreased is 1/5th of original time.
=> 1/5t = 30 or t = 150 minutes.
d = 40 x 150/60 = 100 kms

Example 2 : If price of sugar increases by 33 1/3% then how much decrease in consumption to keep expenditure constant.
33 1/3% means 1/3
Increase in price by 1/3 will lead to 1/(3 + 1) = 1/4th or 25% decrease in consumption of sugar to keep expenditure constant.

All examples in this video can be solved using this.

[anupammishra]

2:20 My first clap 👏 👏 👏 👏 👏 for your explaining the formula of the distance speed and time Just a wow 😮. ... What is the trick you will give to us ❤❤❤❤❤😮😮

[manojkolhe]

This is all I was looking for .Very well explained in English. Looking for more such video s.Thank you sir.

[SathishKumar-okpx]

That one point of same.distance same time same speed.. there solved all my doubt.. Guru ji.. if u see u i will fall to ur feet.. thanks alot sir

[lavanyas]

I regret that im watching this video after 4 years it has been posted ....i feel damn easy on those topics i ve seen in careerride .thank you sir!

[subhp]

Wow~~ i was never listened so obediently in my entire life . Thanks for explaining it so nicely... Hope to see more videos in different topics.. keep it up👍

[-Corvo_Attano]

I always avoid train problems... but after this video i solved many problems ... Thanks a lot sir :)

[deepti]

BEST YOUTUBE channel EVER way better than personal teacher itself really best

[makeenglisheasy]

Excellent Teaching...You have been helping Many Students to fulfill their dreams of getting a Government Job.

[kewtomrao]

Easy approach for Question 10
S' = 5s/7 where S' is new speed and s is original speed
Conv everything into hours
(1+40/60+48/3600)=42/(5s/7)
Hence s = 35

[meetpatel]

Unbelievable explanation, I have learned how to solve problems related to speed, distance and time. Really appreciate your work and Thank You So Much for this.

[RiyaKumari-vtwj]

The best part of this video is that you keep focus on concept

[The_retired_player]

I can't believe you literally provide these excellent videos freely.
This is so amazing! Thank you so much

[neetisha]

I was on the brink of frustration with this chapter but you saved me.... 😘😘😘😘best maths teacher ever

[elusurilathakumari]

Q.(5) To find the difference of time you added T1 and T2. But in Q.(6) To find the difference of time you subtracted the values. In this case i have slight confusion, could you kindly explain it.

[rukhsar]

you are an amazing teacher!! thank you so much sir for your effort.

[Venkimgr]

This is very useful vdeo. I knew 70% about this topic. Now i got more confidence after this class. Really good for beginners also

[AbbeyOnAtkins]

Thank you! I spent 3 days trying to solve a problem using the chart method. Your method was the only one that worked!