Integrating a Function as a Power Series

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[ e^(x^2) ] / x

by integrating the corresponding power series representation for the function.
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How did the x^2n become x^(2n-1)?

EDIT: Oh because the 1/x can be written as x^-1 and then you just add the exponents of x^-1 and x^2n which becomes x^(2n-1)?

HDitzzDH
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can you please tell me if I need to integrate the exponential function from zero to infinity how do I get rid of the infinity, in what Patrick did, there was a +c term in the end, if I have integral from 0-->infinity, everytime I insert the limit my whole term turns infinite instead of giving me an answer. Can you please tell me where I'm going wrong?

farheenjawaid
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And to find the radius of convergence for that?

nataliep
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this is fucking impossible i need healing.

XpertiCON
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This has been one of the best videos : thanks once again

odinheim
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If the integral was from zero to infinity, then what? How do we solve then? Please reply urgent

farheenjawaid
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For what reason would you integrate a power series? It's nice to understand how it's done but I don't see why it would be done in the first place.

josephlauletta
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Wait, why e^x^2 is equals to sum of 0 to infinity of x^2n / n! ?

fathanh
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sir, , , e^(x).x^(-1) pls solve quick

AmitSharma-jmtg
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If the integral was from zero to infinity, then what? How do we solve then? Please reply urgent

farheenjawaid