Kotlin Newbie To Pro - WHILE LOOP - Part 12

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In this video you will learn how to execute a certain piece of code several times in a row.

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Hi, I'm gwynn from philippines. I just turned 13 and my father told me that I should learn kotlin as my first programming language since it's going to be one of the indemand programming language in the future. Its my 3rd day watching your videos. here's my assignment.

assignment 1:
var userInput = readLine()!!.toInt()
println("Let's count from $userInput down to 0:")

while (userInput >= 0){
println(userInput)
userInput--
}

assignment 2:
println("Enter number 1:")
var num1 = readLine()!!.toInt()
println("Enter number 2:")
var num2 = readLine()!!.toInt()
var numTwo = num2 //to be used for println since it will not be affected with decrementing

var result = 1

while(num2 != 0){
result *= num1
num2--
}

println("$num1 to the power of $numTwo is $result")

gwynnanimations
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I forget to comment on how much I love your tutorials, because I'm already ready for the next one. Thank you so much for making these tutorials. And I know how much time these can take, especially when you have to show different areas of the screen and so on. Thank you so much for all your efforts. I hope your channel grow more and more as time passes. Good luck ❤️

soontaek
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fun main () {
println("Enter number 1: ")
val x = readln().toInt()
println("Enter number 2: ")
val y = readln().toInt()
var a = y
var power = x

while (a != 1) {
power *= x
a - -
}
println("$x to the power of $y is $power")
}



// I did it like this way and got the correct answer. Great video bro thank you really liked it

aakashkumaryadav
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that's a rally an issue, thanks for content 4 years old but still the best qualitiy ever.

karllviii
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fun main() {
println("Please enter a number: ")
var num = readln().toInt()
println("Lets count from 10 down to 0:")
var i = 1
while (i <= num) {
println(num - i)
i++
}

}

gokhrustali
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Hard one was difficult when using while loops instead of just .pow() . Here is my solution though it relies on the intial value of a number to be 1:

var firstNumber = 0
var secondNumber = 0
var intResult = 1
var indexer = 0



println("Enter Number 1: ")
firstNumber = readLine()?.toInt() ?: 0


println("Enter Number 2: ")
secondNumber = readLine()?.toInt() ?: 0



while (indexer < secondNumber)
{
intResult = intResult * firstNumber
indexer++
}

println("$firstNumber to the power of $secondNumber is $intResult")

loganwhite
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Dude thanks for this series this is awesome!

yanikhohner
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For the second homework:

fun main() {
println("Enter the number:")
val firstNumber= readln().toInt()
println("Enter the power number:")
val secondNumber= readln().toInt()
var result= firstNumber
var i= 1
while (i != secondNumber){
result *= firstNumber
i++
}
println("The $firstNumber to the power of $secondNumber is $result.")
}

MoonwalkerOfDreams
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for me I will like to give another way for your hard problem:

fun main(){
println("Enter the base")
val base = readln().toInt() // user input
println("Enter the exponent")
var exponent = readln().toInt()// user input

// Initialize result to 1
var result = 1

// Use a while loop to calculate power
while (exponent > 0) {
// Multiply result by the base
result *= base

// Decrease the exponent
exponent--
}

// Print or use the result
println("Result: $result")
}

djroo
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Many thanks for your videos
This video/step was an opportunity to show how to run code step by step :) (one great advantage of an IDE)

guy
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Thank you for all your work Philipp! You really helped me a lot. Your way of teaching is very effective and easy to follow! Please keep up the good work! Dankeschön

pengottv
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fun main(){
println("Please enter number 1 : ")
var num1 = readLine()?.toInt()
println("please enter number 2 : ")
var num2 = readLine()?.toInt()

if(num1 != null && num2 != null){
var result = 1
var i = 0
while (i < num2){
result *= num1
i++
}
println("$num1 to the power of $num2 is $result")
}
}

whoim
Автор

println("Enter a number")
var number=reader.nextInt()
while (number>=0){
println(number--)

}

abbasgaming
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fun main() {
println("enter number 1")
var number1 = readLine()?.toInt()

println("enter number 2")
var number2 = readLine()?.toInt()

var i = 1
var result = 0
if (number1 != null && number2 != null) {
result = number1

while (i < number2) {
result *= number1
i++
}
}


println("$number1 to the power of $number2 is $result")

}

murtadhajafar
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How can I toss you a dono the easiest where you get all of it? I want to do that when I complete this series over the next few weeks. Thank you for all of the work you have done for people that like to learn with quality content for free.

elghs
Автор

fun main () {
println("Enter number 1: ")
val x = readln().toInt()
println("Enter number 2: ")
val y = readln().toInt()
var a = y
var power = x

while (a != 1) {
power *= x
a --
}
println("$x to the power of $y is $power")
}

ekafrancium
Автор

Thanks for video, Philipp!
Here is my solution:

print("Enter the number: ")
var number = readLine()?.toInt()!! //it's definitely could not be null due to javadoc of readLine() function
println("Lets count from 10 down to 0:")
while (number >= 0) {
println(number--)
}

sintaksist
Автор

fun main() {
println("Enter no. 1")
val n = readLine()?.toInt()
println("Enter no. 2")
var m = readLine()?.toInt()
var ans = 1
if(n!=null && m!=null){
while(m!=0) {
ans *= n
m--
}
}
println("Answer is $ans")
}

kush
Автор

// calculating power of num

println("enter the num")
val num = readLine()?.toInt()

println("enter the power")
val pow = readLine()?.toInt()

var ans =1
var i = 1;

if(num!=null && pow!=null){

while(i<=pow){

ans*=num * 1
i++

}
}

print(ans)

Luffy_
Автор

This is the Harder version of code in Homework
fun main(){
println("Enter your 1st number:- ")
val x = readln().toInt()
println("Enter your 2nd number:- ")
val y = readln().toInt()
var a =y
var power = x
while (a!=1){
power *= x
a--
}
println("$x to the power $y is $power")
}

anmoltrvd