Applying Newton's Law of Cooling to warm oatmeal | First order differential equations | Khan Academy

preview_player
Показать описание

Missed the previous lesson?

Differential Equations on Khan Academy: Differential equations, separable equations, exact equations, integrating factors, homogeneous equations.

About Khan Academy: Khan Academy offers practice exercises, instructional videos, and a personalized learning dashboard that empower learners to study at their own pace in and outside of the classroom. We tackle math, science, computer programming, history, art history, economics, and more. Our math missions guide learners from kindergarten to calculus using state-of-the-art, adaptive technology that identifies strengths and learning gaps. We've also partnered with institutions like NASA, The Museum of Modern Art, The California Academy of Sciences, and MIT to offer specialized content.

For free. For everyone. Forever. #YouCanLearnAnything

Рекомендации по теме
Комментарии
Автор

Keep changing colours, it's way clearer when you do it! And thank you so much for all of this!!

claudiopintoalmeida
Автор

More helpful than my teacher but shhh
Color changes helps separate things a bit, keep it.

mojoemahn
Автор

Thank You so much Sir, you're a living legend. I'm sorry you had to change colors because of us learners but you literally saved our backsides. I couldn't do this question without you. Keep up the great videos.

danialraja
Автор

Well I guess I have to buy a culinary thermometer. I thought That figuring out rate of cooling would be a simple formula. I want to try brewing coffee with French press method, which requires the water to be slightly cooler than boiling, 190° the video I watched had said. So I thought instead of buying a thermometer I could just figure out how long to wait after the water reached a boil, considering what the room temperature was according to the thermostat for heating, Than add the water to coffee grinds. All I can say is Damn.

jonbarnhard
Автор

i love you! saved my Maths IA. I'll reference you dw

auriginaladhi
Автор

Thank you so much for this video my savior Mr. Khan

envisageiwnl
Автор

This is amazing how a person who died 400 years ago had this ability to figure out how much the temperature will change after a certain period of time :o I’m really impressed

sajjadkareem
Автор

Why is the negative in the front of k needed? Does k have to be positive? Couldn't the final output be the exact same without it?

jasonmahoney
Автор

Do a version where there is no color change and there is color change.

p.l.apostol
Автор

Keep changing colors, its really helpful and interesting !!

and Thank for saving my life ^, ^

saadasm
Автор

thank you sir, which software are you using to teach .

KennethAzemafac
Автор

But according to the equation that you have provide T(t) = Ce^(-kt) + t (ambient) it contains no information on the initial temperature of the body so if the body is kept at very high temperature the equation says it takes the same time which doesn't make sense. Can anyone please help me with that.

sriram-wein
Автор

Does mass effect the cooling process as large mass system takes longer time to cool for the same temperature as compared to the small mass system of the same material ?

dhairy-kumar
Автор

sir please add these kind of concepts in the calculus playlist

saipandala
Автор

Thank you Khan Academy :) You are better than my teacher *hands down*

AcornMT
Автор

So, I guess this is just a sample of the basic formula? Something like oatmeal would cool at different rates in different parts of it. Like center or lower part if it would somewhat insulated by the surrounding hot oatmeal. Then you have surface area, container properties and dimensions. Perhaps air movements, humidity, and a lot of other variables to the point where trying to do it with math would be very time consuming to calculate and verify.

RichardsWorld
Автор

you are doin great work homie...keep this up

angeljohn
Автор

Looks like you forgot to include the neg in k when you started solving for the final answer so final answer should be negative

kevmck
Автор

What if we have to cool down our oat meal to a room temperature i.e. in this case 20 degrees? Substituting 20 in our final equation gives us a zero. How do we deal with this situation?

kamranaliahmed
Автор

Yo 80 degrees C is super super hot for oatmeal, that’s 176 F...

xbony