Intro to Circular motion- Centripetal Acceleration and Apparent Weight
Apparent weight due to rotation of earth.
Calculating the Apparent Weight in an Elevator
Circular Motion Problems 5 Weightlessness on a hill
How to Calculate Apparent Weight in an Elevator (at Constant Velocity)? #class11physics #apphysics
Circular Motion | Lecture 10 - Real and Apparent Weight
Apparent weight in a Lift/Elevator||Class 11 Physics || Laws of Motion
Комментарии
Great video! Explained everything simply and clearly. Keep it up!
chonkyraccoon
I get the working, but inserting the values gives me different answers..
mathematicism
Acceleration changes based on the distance of the mass from the center of rotation. It's not the same movement, albeit I would prefer hip fire in a cqb situation.
HeirPlain
Thats great everything is clear now ... Thank you sir
whhy
been drawing FBD's for 2 days now. at the top Fc and Fg both point down i am amusing there is a Fn also pointing down. then there is supposed to be an opposing force which i assumed to be Ma but that doesnt seem to work out with the value i worked out for it. we did it with Fc= -mg +/- Fn = (mv^2)/r but on the top considering Fn is positive and solving for Fn you get Fg + Fc but im pretty sure its supposed to be mg - Fc
gerakore
ok i finally figured it out. in Fnet=ma at the top ma is negative since it points toward the center and at the top its positive. jeez that was causing way more confusion than it should have
gerakore
I get N=252 N for the top case, N=720 N for the bottom. Weight = 686 N
diegomercier
@5:38, why are you not multiplying 70kg by 9.8? Also, why are you not multiplying your 70kg mass by v^2? Why do you write the last step as just instead of