Convolution (Solved Problem 1)

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Signal System: Solved Question on Convolution operation.
Topics Discussed:
1. Solved example of convolution.
2. Convolution using Laplace transform.
3. Problem's solution using the properties of convolution.

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limit in 2nd case should be 0 to t....at 9:30

gladiatorsblog

Thanks a lot sir!!! Your videos are really helping me prepare for my exams Jai Siya Ram

BhavikRaghav

I think in method-1, h(-T) should be shifted towards right to get h(t-T)

saisunayan

professor when you convert from h(-𝜏) to h (t-𝜏). The curve should shift right instead of left. This is because the shifting operation is performed on the 𝜏 component only but no the whole (t-𝜏) argument. My professor taught us to let another function g(𝜏) = h(-𝜏), then perform subtraction or addition to g(𝜏) so that h(-𝜏) becomes h(t-𝜏), in this case we perform subtraction: g(𝜏-t) = h (-(𝜏-t)) = h(t-𝜏) (note that the shifting is performed only on 𝜏 but not the whole argument). Finally, because of g(𝜏-t), -t means that the whole curve shifts to the right by t units. Therefore it should shift to right instaead of left.

c.cody.

There is a mistake at 9:36
In second case : for t>0 integration limit should be from 0 to t *not* from -infinity to infinity.

MdRaiyanRaziBEC

sir the limits of integration must be from minus infinity to 't'.

pratiushanand

Great videos keep up the amazing work!

dwayneanthony

we can write the given func as unit signals and then use u*u as ramp and get the answer directly using this method saves a lot of effort :)

hardikjain-brb

Sir when will you start Fourier transforms?

rohithpokala

why is the value of integration = t at 9:36?

inspireeshwar

Sir complete signal system as soon as possible

SaikatPodder

I watched previous lecture but I have not understand yet why shift isn't to right, could you explain it more, please ?

RahmaElsaeed-cfru

We can use trick # u(t+a) * u(t+b) = ramp(t+a+b) to solve question

greenemerald

Sir why you take limits as -ilinfinity to +infinity
because signal overlaping is from '0' to 't'

akashjagtap

Sir, in case no.2 how the result of output as "t" was came by the integrating w.r.t tau from -inf to +int

zvirus

8:20
Integration of zero is equal to a constant!

GimmeMonie

Why are we not taking 3 cases, {- infinity, 0}, {0, t}, {t, infinity}.
Also IF we are only taking 2 cases {- infinity, 0}, {0, infinity}, then in solution its showing y(t) = 0, t<0 and y(t) = t, t>=0.
I didn't get where did t to infinity portion went ? If its 0 then why in solution we took, t>=0

kritikabhateja

In case II, t>0 range, why is the limit [-∞, ∞]. Wouldn't it be [0, ∞]? h(t) overlapped x(t) from 0.
confused about it. Hope you will help.

asmaulhosna

How invees Laplace of 1/s² is r(t) y not t

abhaykondru

sir convulated u(t-1)+u(t-5)-u(t-3)with ramp function

kunalchouhan

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