Frequently Asked Java Program 27: How To Count Words in a String

Topic : How To Count Words in a String

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[jashuvadevisetti]

Easiest way to solve :
class Test{
public static void main(String [] args) {
String str = "hello walcome to java programming";
String []tokens=str.split(" ");

} }

[rajendramahapatra]

There is one more easy approach.
String str = “Welcome to the Java tutorials”;
String strArray[]=str.split(“ “);
System.out.println(“The number of words in a string is “ + strArray.length);

[harshitranjanrai]

public static void main(String[] args) {
int count=1;
Scanner sc=new Scanner(System.in);
String s=sc.nextLine();
for(int i=0;i<s.length();i++)
{
if((s.charAt(i)==' '))
{
count++;
}
}
System.out.println("Number of words in string = "+count);



}



There is one less condition and giving same output

[chinna]

One more easy approach. String sentence = "Java easy peasy when we practise and explore";
String[] words = sentence.split("\\W+");

[charanbudama]

can we use this ?


String s1 ="This is a java program to find the words in the string";
String [] s2 =s1.split(" ");
System.out.println("Number of words are " +s2.length);

[MartinoxxHD]

You can actually use the Scanner class for counting letters:





private static int cntWords(String phrase) {

Scanner in = new Scanner(phrase);
int cnt = 0;
while (in.hasNext()) {
cnt++;
in.next();
}
in.close();

return cnt;
}

[Developer]

int count = s.replaceAll(" ", "").length();
System.out.println(count);
i think this looks pretty easy
love you Sir for ur dedication to videos

[pankajsahu]

String S = "Hidndustan India Ganga";

String [] words = S.split(" ");

[nileshpardeshi]

Hello Pavan sir,
This program fails if we haven't entered any string as input, the count is showing 1, bcoz by default count is 1. Another thing if the user entered multiple spaces as input then what logic needs to add to find the total count?

[raghusundaram]

import java.util.Scanner;
public class CountwordsinaString {
public static void main (String args []) {
Scanner in = new Scanner(System.in);
System.out.println(" Enter a String");
String str=in.nextLine();


int count=1;
for(int i=0; i<str.length(); i++) {
if(str.charAt(i)==' ') {
count=count+1;
}
}
System.out.println(" numbers of word present in the string is "+count);
}
}

[saurabhpadwal]

It's very easy solution...
Thanks brother...

[EdClarkHYCT]

Awesome solution 👏🏾👌🏾👍🏽!!! Thanks for this!!!!

[shailendraverma]

Thank you sir ! Really Helped allot ❤❤

[tapaskhandai]

For loop should be i<=s.length()-1. Anyway here it is doesn't matter

[saqlainquazi]

i<s.length-1 or it should be i<s.length

[dilrubaahmed]

some days earleir, Mr. Pavan had shared a link for a new youtuber for learning java and other stuffs.Do anyone know what is the name of the channel?

[hefshineatulashokugalmugal]

there are one test case fail in your code ex." atue auah iaajja " output require=3 but your code output is 4

[Shreenidhi]

I have one doubt, If we have space in starting of the sentence, we need to keep cunt as 0, but t wont work for count 1.Please suggest!

[subhamanand]

why the count variable is intialized with 1 not zero?

[nainagupta]

one confusion : in if you used compare "==" for first condition and for 2nd "=" only assignment could you please explain