Bézout's identity: ax+by=gcd(a,b)

preview_player
Показать описание

Bézout's identity, ax+by=gcd(a,b),
Euclid's algorithm, zigzag division, Extended Euclidean

10% off with the code "TEESPRINGWELCOME10"

Equipment:
---------------------------------------------------------------------------------------------------
Рекомендации по теме
Комментарии
Автор

You explain this so well and the only example I have found that I can actually follow, thank you! 😊

wobblyjelly
Автор

I was lazy and didn't want to watch an 18 minute video!
Now, I am more than grateful I clicked and watched. Thank you, best explanation ever!

halik
Автор

Thank you for your upbeat atittude that made me feel a lot better!

pablosabogal
Автор

Thank you for your explanation, it helps my report so much. And I really like your smile. Thank you

khoaang
Автор

BIG Thanks man your videos helps a lot as a collage student

wajdefadool
Автор

Nice!! My favorite part is quantifiers "forall" and "exists":D

MathForLife
Автор

This was the best explanation ever! Thank you! You saved my maths exam. :)

chloinger
Автор

Thank you, you explained it so well that I am confident in passing my discrete maths exam

lilianavalente
Автор

Cool fact: Bezout's lemma (that's how I learned it) is actually applcable in any group that's similar enough to Z. I learned a general form of the lemma in a course on group theory.

Of course in group theory the notions of gcs and lcm are defined more generally in terms of subgroups and their generating sets. Interesting stuff if you're into that sort of thing.

shacharh
Автор

for people unfamiliar with the Euclid's Algorithm, it's actually based upon the lemma: Suppose b = aq + r, then gcd(a, b) = gcd(a, r). You can prove this lemma by contradiction in ~8 lines

dariushuang
Автор

Thank you for a very nice explaination. Keep it up 🙂

tejadamichelle
Автор

I have a few suggestions for videos. Here’s just one:

Two circles of radius R intersect each at exactly two points. Lines are drawn from each of those points to the center of one of the circles. Those lines and the inner arc of the other circle define a region.

What is its maximum area?

NotYourAverageNothing
Автор

Woah!! Wonderful explination Love from indiaa💗

psrs
Автор

It feels so weird to have done calculus without having learned this stuff.. thanks!

maaikevreugdemaker
Автор

Damn, this is flipping awesome explanation! ♥

shrameesrivastav
Автор

Thank u. U may arrange a video on Bezout identity and Uclid Algorithm.

kantaprasadsinha
Автор

damn this was a really clever solution, props to bezout!

doodelay
Автор

11:45 "I will call this x naught and y naught because why not" is what you should've said! you missed a pun opportunity. I'm disappointed.

BigDBrian
Автор

Please do a videos on how to find inverse of a function

jacksonsingh
Автор

this is better than the resources my uni has thanks

chronicsnail