Classical Mechanics Solutions: 1.11 The Path of a Particle

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[josephdonahue]

When you square each term... don't you have to square each entire side-- and therefore have cross terms hanging out? This would be +2(xy)/(bc) on the RHS and +2cos(wt)sin(wt) on the RHS. You could then sub again on one side(in terms of the other) and cancel to give what you have around 3:05.