Physics - Pully on an Incline (1 of 2) Frictionless

This lecture will cover Newton's Second Law: F = ma.

Problem Text:
A 5kg mass is placed on a frictionless incline making an angle of 30 degrees with the horizontal. A rope is attached and positioned over a pulley at the top of the incline. A 6kg mass is suspended from the free end. What is the acceleration of the system.

[JasonStonebraker-hc]

This was posted 11 years ago and it is still top tier teaching. Thank you for the assistance.

[kphillips]

Being able to solve these problems and the ecstatic feeling of when I am able to figure them out, with a little help from you and your videos, reminds me of why I am studying physics to begin with. Thank you so much sir

[Aristothink]

I like when the teacher does the math at that very moment, because that is how the student will do... Good quality videos as ALWAYS Michel ! Please, never stop this amazing work and contribution to all physics lovers...

[dhiashanshal]

It is important, that a teacher understands what he is talking about, so this guy does

[tatusaalasti]

6:36 this is a rare phenamenon called schrödinger's physics professor, when the professor actually reaches quantum state

[haydenpurewal]

i have a really bad univierity physiccs proffeser and this really clears up a lot of things, well done going over the formulas and how they interact with each part of the question, i will be explaining this to my friends shortly

[cooleslaw]

Much clearer and more concise than my textbook. Thank you for uploading this.

[MichelvanBiezen]

Luciano,
You only need to consider the tension in the rope if you are solving the problem using free body diagrams.

[dawsondemontiney]

I would liket to thank you for the time that you put into these videos. I am attending MSU Bozeman and the instructor is no where as good as you, I have a lot better understanding of tension and these friction because of your videos. Thank you taking your time to make these.

[nathancc]

Still cant believe this lectures took place 10yrs ago
Im in 9th and thanks for helping me for IIT-JEE prep
Love from India❤❤
Your lectures are so good can understand literally every thing and i find a meaning in it and it is not at all boring.

[AshishSharma-elhz]

Sir ..you taught me perfectly..
Thanking you equally the perfection of this leecture
.god bless you sir.

[nachomama]

Thanks so much. Explained way better than my text book. I feel so much better watching this.

[yahya-mzyt]

I would like to thank you and my left ear for your efforts.

[keylime]

This saved me a few hours, ima go back to work now :)

[andreabudnick]

This was absolutely amazing!!! Thank you so much. You are such an amazing teacher!

[charityjeffery]

Siryour explanations are excellent but please may you brighten oh bring the camera close to the written problem 😢

[BlightBlaze]

My left ear enjoyed this. good vid though

[KrishnaGupta-hfod]

I have a confusion that at 3:08 he breaks mg into its component then he breaks it in a format of x axis and y axis and I have studied that x axis is cos theta and y axis is sin theta then how come he wrote cos theta on y component because if u see then it will be y component of mg and should be sin but he wrote cos, can anyone tell me why?

[MichelvanBiezen]

Murathan,
Good luck on the test.  Let me know how you did.

[anthonyreyes]

shout out to this guy for teaching me in under 10 mins