Simplifying Log Expression

[lucifermorningstar]

Love seeing this channel grow.. Well deserved Sr.

[swagger]

damn ty i have a logarithm test tmr this is a good refresher

[Vawltt]

Thank-you so much, we're just learning about logarithms in class. I'm always keeping an eye out for your videos they are amazing.

[thegoofiestgoooberr]

log2(16) + log2(sqrt(2))
log2(16) + log2(2^(1/2))
4 + 1/2
9/2

[franciscoalcaide]

Thank you! Really like these videos as mental excercise!

[ArnavvvvV-bz]

Just wanted to let you know, i just love this channel, i have been getting solutions to my question and this kind of helps to avoid algebraic mistakes in the lomg run...Thanks!
Keep doing what you do! It definitely helps us and is interesting as well

[oilman]

I just started watching his you tube shorts and I wish all Math teachers teach like him. His explanations and use of arrows makes it easier to learn and understand the flow of the problem.

[mhrafi]

This channel is helping me on my revisions, thank you sir❤️

[EdwardTHead]

I'm unemployed and not in school. I just like math.

[joeythreeclubs]

I like the pen? Thing he's using. Chalk always gives me shivers so it's appreciated

[Just.a.fellow.stranger]

If i had a math teacher like you back in high school i probably be a engineer by now

[misterninja]

This person just taught me what i couldn't do for quite some time now in just 60 seconds. 🙏

[saidfarid]

Hello Professor
Thank you so much for your interesting lessons and excellent explanation, i do appreciate your job.

[Janarcus]

If I had your explanations in highschool my grades would have been so much better, now I just do math for fun :)

[आपलामानुस-खष]

I am not student either. But I like maths and his way to teach. Really great videos

[mrlolcat]

This is very clever, im glad I solved it before the video started

[imivanm]

Idk why I’m watching this. It’s giving me anxiety.

I’m going to have dreams about not studying enough for a test.

You got yourself a subscriber tho 😂

[raysshine]

Another method is using the log laws so you can decompose log base 2 of 16root2 into log base 2 of 16 + log base 2 of root 2 = log base 2 of 2^4 + log base of 2^1/2= 4log 2 of 2 + 1/2log 2 of 2 = 4+1/2 =8/2+1/2=9/2

I think the method (solving for x by turning the log expression into an exponential expression) in the video is neater if you want to arrive at a solution without any hassle.

[luisclementeortegasegovia]

Nice and well explained, good didactic!

[sustrata]

I just realized you can also turn 16√2 to 2⁴•2½ which is 2^(9/2) and logging it to base 2 leaves 9/2 = x