F=ma Cylindrical Coordinates| Equations of Motion| Learn to solve any problem

Learn how to solve f=ma problems with cylindrical coordinates step by step.

A smooth can C, having a mass of 3 kg is lifted from a feed at A...
Determine the force it must exert on the 0.5-kg smooth cylinder...
A car of a roller coaster travels along a track which for a short distance...

Book used: R. C. Hibbeler and K. B. Yap, Mechanics for engineers - dynamics. Singapore: Pearson Education, 2014.

[guulkutaam]

The way of explanation and the vedeo is something special, good job, may allah protect you.❤❤

[Minion-cqzx]

I cant solve dynamics problems.What can i do.I know concepts but cant solve.😢

[jahanzebabbasi]

bro u literally helped mepass my exam 6 hrs..i salute u teacher!

[stananas]

Thank you so much, Professors really became lazy after covid

[michaelmcdermott]

Thank you! the Hibbler text explanation for cylindrical coordinates is horrible, but this video is fantastic!!

[theartistkiller]

Hello, when drawing the FBD for the first problem @ 4:12 how did you know that the normal force N is acting on the can 30 degrees below the radial axis? You said that the normal force is always perpendicular to the tangent [of the path] but when did we find the tangent to figure out the position of N?

[mohibjadoon]

You can't imagine my happiness when I found out you also make videos of dynamics.
Love you bro
Keep it up

[hatimamin]

At 6:28, y does the FBD for the second question not have the weight of the cylinder acting on the rod in the transversal axis?? Since the weight was used in the FBD in the first question.

[fikreselassiesolomon]

Hello!
Example 2: the weight is ignored, which is in the direction of θ. Considering the weight I got F = -5.8 N.
I appreciate if anyone check this and reply.

[SettNaing-id]

Thank you Sir.
May Lord bless you always.

[matteobekink]

These videos are really nice . I have a question though . At 7:19 the normal force is included into the FBD following the idea that its normal to the tangent line. But then the force F is included in the direction of theta. Why is it that we dont always assume there is a force parralel and one perpendicular to the tangent line rather than making conclusions based on the structure?
If I was to assume the first, would it be ok or is that incorrect ?

[Jimmysmith]

in the second example I believe you didn't multiply dr^./dtheta^. by theta^.

[lungumatei]

why on example 3, is there no Normal force acting on the car??

[mathematics]

very good explanation and nice understanding of the topic.subscribed

[benjaminjones]

I don't understand psi and how its relevant at all

[Sigma_J]

7:11 Hey man in the FBD why we don’t have to out the weight of the cylinder. Thanks

[e-nes]

ar = -8, 73 will be m*ar=0.5(-(-8.73)) =0.5*8, 73 because left is negative ? at 7.32

[arwatariq.]

in the second example why did we take the r and theta axes in the other direction that we usually do? is it because we found psi as -ve ?

[meenakamath]

Give example while teaching. Then only goes in head.

[muheezolamilekan]

Thank you very much, so happy that you also have videos for dynamics