Stress, Strain and Young's Modulus - A Level Physics

This video introduces and explains stress, strain and Young's modulus.

When revising for your exams it may seem like you are under stress and strain, however, they are quite different but they do allow us to investigate materials. The stress strain relationship can also be calculated giving Young's modulus (or the Engineering modulus).

Thanks for watching,

Lewis

This video is recommended for anyone studying A Level Physics in the following exam boards:
AQA
CIE
Edexcel
Edexcel IAL
Eduqas
IB
OCR A
OCR B
WJEC

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[zahrakosgi]

In just *3 minutes* you cleared a concept I was banging my head on for 3 days! Amazing! Thank you for such an awesome and informative video!

[gentlefistinfinity]

I am now learning this stuff for my final year project and you were super helpful bro. Thank you very much and God bless.

[kuachii]

1:30 i blinked i thought my brain shut down for a minute and i didn't realize. i had to rewind the video lmao

[andysun]

Jezz this is way damn better than my physic prof's mad lecture

[Fudgey]

Thank you for these videos. You're going to be responsible for my (hopefully good) unit 2 physics grade haha

[fabiankabas]

Very clear explanation, thank you!
Helped me out a lot with my studies in biomechanics!

[camilleflores]

Great video demonstrating the difference between stress and strain. Interesting explanation on young module’s law I like how you draw out all of the formulas.

[soramin]

I love the way you explain things
Thanks for the lessons

[EmTom]

I probably shouldn't be watching this the day before my physics exam :/

[amjadmcheik]

Most useful video of all time thank u so much

[johntindell]

Thank you very much for your honourable and altruistic work. Your videos are immensely helpful for me to understand the profound philisophical significance of physics.

[pbsciencetacular]

Thank you very much for this useful video

[perpetualtom]

Your're awesome man! Good job i've found you, doing a practical on Hookes Law tomorrow where we have to use micrometres to find the cross sectional area of wire then apply a force to it. What more can you tell me?

[rj]

Higher the youngs modulus of an object, harder it is to deform it

[beckydonaldson]

Great video! Thanks! :D Keep up the good work :)))

[ron]

I don't like it when people make their Xs like that! It looks sort of like a half-assed, infinity symbol or lower case alpha and nothing like an X. When you're looking through hand written calculation, from different people, clarity is a God send.
Good video though, clean and thorough.

[TopG]

Stress = pressure, this makes it easier

[mingyangli]

Very useful video, easy and understandable, thanks!

[onur-]

how can i find E(elastic modulus ) from psi

[ha_]

Thanx for such an outstanding explaination :')