Newton's Method

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Disclaimer: This video is for entertainment purposes only and should not be considered academic. Though all information is provided in good faith, no warranty of any kind, expressed or implied, is made with regards to the accuracy, validity, reliability, consistency, adequacy, or completeness of this information. Viewers should always verify the information provided in this video by consulting other reliable sources.

[battlefieldtroopersEA]

jeez its that simple! it took my teacher 2 hours to explain this. he left me with a lot of questions and a headache.thanks :)

[blessed]

This is the best explanation for this topic

[tommystaunton]

This was the best explanation I’ve ever seen

[theodoresweger]

Many calculators use a similar system very useful for unusual problem's that are simple enough to differentiate Thank you very much.

[gregorybillias]

Always a video of yours there to clear my brain from misundestrading mathematician things! Love from the Mathematics department of Univesrity of Patras (Greece) !

[michaelbauers]

For square roots, this simplifies to the Babylonian method of Xn+1 = .5*( Xn + a/Xn), where a is the number you want the square root of. It's not unlike a binary search, where you simply average the best current guess with the result of trying to divide a by the best guess. This effectively halves the error term each time. Pretty clever, those Babylonians.

[_KESINIB]

thank you to infinity sir...I wish u should have been a proffesor of my university

[theobserver]

Damn, this is satisfying when learned.

[marlenepachner]

but how do i find a good start value for more complex functions?

[nabeelayusuf]

Thank you very much. You just saved me

[akolangto]

I just found it now. Thanks! You're good sir.

[hadhoud]

what to do if we don't know the final solution

[andunyaa]

What is The Derivation of Newton's Method ?

[ivanreyoroc]

X5 exacts the value of square root of 2

[sebastianbalbo]

It seems identical to INDIAN METHOD OF 12 century amazing

[tv..]

<나의 초간단 유도>
r(2) < a 에서 우변으로 이항하면 0 < a - r(2) 양변 제곱하면 0 < a^2 - 2a*r(2) + 2
2a * r(2) < (a^2 + 2)
r(2) < (a^2 + 2) / 2a 끝!!! <- Newton-Raphson Method에서 구한 결과와 같음.

[tfgaming]

Sir, I am not allowed to have a calculator, how will I be able to do this?

[theobserver]

I legit calculated √2 all the way to x5...

[npc_male]

i thought i was cooked becuz even an indian guy coudnt explain this good thx

[KJJHN]

What I'm not quite sure about yet is where x0 or sqrt(2) came from. If only the function is given, how do you guess for the X0? "pick something close to the answer" I have a function, no solution, do i graph it an look for x intercepts? Your've videos are great, but I'm a bit dense. Suggestions about finding x0?