EASY WAY TO SIMPLIFY BIG FRACTIONS

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Isabel Explains a quick way to simplify fractions, no matter how big they are!

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Do you know another way of simplifying big fractions?

IsabelExplains
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Thank you Isabel, you have made math easy to understand!!! I absolutely love

StorytimeWithStelita
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thanks!! i have a test tomorrow and wanted to fully understand this

carolinebrennan
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this makes so much more sense now thank you!

emmaraposo
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bro not only does she have a class to teach but she does this on youtube, just saved my test score from 0 to a possible A+, thank you so much this is so useful!

Artifact
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Barely comment in videos but I have to comment on this one. You just saved a life. Thanks a lot. Also subscribed

ebubesunday
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Amazing video i learned this method very clearly

ruchigupta
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Oh bless you woman! Bless you bless you bless yoy

burntt
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Thank you isabel mam its easy method thank you so much 🙏🙏

SrinuDanthuluri-vtti
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Thank you so much for the video! I finally understand the fastest and easiest way to simplify the big fractions. ❤❤❤

ningmak
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HOW TO SIMPLIFY FRACTIONS THE EASIEST WAY:
If the difference between the numerator and denominator is 1, the fraction cannot be simplified.
A. Ask: does the numerator go into the denominator evenly (i.e. without any remainder)?
If yes, proceed to B.
If not, proceed to C.
B. Great! The simplest fraction is 1 over the number of times the numerator fits in the denominator. (e.g. 20/60, 20 fits evenly 3 times, hence 1/3.)
C. Write the remainder, (e.g. 20/46, (20 fits 2 times in 46, with a remainder of) 6.) to the right of the fraction, and ask: does the remainder go evenly into the numerator?
If yes, proceed to D.
If not, proceed to E.
D. Great! The "remainder" is the Greatest Common Factor. Divide both the numerator and denominator by the GCF/remainder to have the simplest fraction.
E. Write the "new remainder" (using the last example, 20/46, 6 fits into 20 with a "new remainder" of 2) to the right of the previous "remainder", and ask: does the "new remainder" fit evenly into the previous "remainder" (2 into 6)?
If yes, proceed to D.
If not, proceed to E.
Please, (with your amazing talent, ) produce a video demonstrating it.

//Euclidean Algorithm.

iqfncmq
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Thank you so much! Just what I needed!

lovely
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You can find the gcf by finding all of the prime factors of both numbers and multiplying the shared prime factors. For example 36 and 44. 36’s prime factors are 2, 2, 3, and 3. 44’s prime factors are 2, 2, and 11. Both 36 and 44 share the prime factors of 2, and 2, so you multiply 2 and 2 together to get a gcf of 4. If your numbers only share 1 prime factor, then that is your gcf is that number. If you have no shared prime factor, then the gcf is 1.

Edit: Forgot to say that overall this video helped me a ton for my shsat prep as you need speed as well bc it is a timed test

RestInPieces
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You can find the GCF if you divide both numbers, then divide the remainder into the smaller number. Repeat step until you get no remainder and the GCF is the number you divided into that gave you no remainder.

171/228 is 1r57 then 57/171 is 3 with no remainder so GCF is 57

BzBlade
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Thank you so much for thisn break down

briannaeaton
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Thank you, thank you, thank you, thank you so much I was searching for this all over YouTube

sudarshanagupta
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I’m confused why 57 is the # to divide? How did you figure that one?

charlottegrigg
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Not a very clear explanation. Where did 3 & 57 come from? Need to break the steps down more.

akrause
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I am currently in 8th grade, and this will help me on my maths test!

Rami
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How far up do you have to go in prime numbers?

cheryllb