Intersections of Two Planes Part 2

This lesson shows how two planes can exist in Three-Space and how to find their intersections. This is the second part of a two part lesson. This lesson was created for the Calculus and Vectors (MCV4U) course in the province of Ontario, Canada.

[appcookie]

He was just working through it -- Even if it seems trivial, it's nice to have a breather and think of what's been done while he's doing the simple stuff.

[georgejohnson]

Great video, something I haven't been able to find on Khan Academy. Just one suggestion, people watching videos about intersection of vectors do not need you to explain how the subtraction of two negatives works!

[Ratj]

Very helpful, it makes much more sense now.

I'm still stuck on a question though. It asks for the equation of the plane that passes through a line of intersection of two other planes, and then perpendicular to another plane. I must be overcomplicating it but I'm very lost....

Thanks for the video!

[HeyyyItsCharlene]

Instead of parametrizing, could you also take the cross products of the normal vectors of both planes (Red plane: <1, 1-3> Blue Plane: <1, 2, -1> ) to find the normal vector? I also got <5, -2, 1> as my answer and I was too lazy to the whole systems of equations thing you did

[awesomeidan]

Hi great video! Why did you take 5, -2, 1 from that part of the parametric equation? Also, I learned a way where you simplify it instead of keeping it in the 3 equation form you have.

Would it be possible for you to show me a way to find the normal vector from that form instead?

[DogeFrom]

+George Johnson Some people like detailed clarification, you know.

[omrdso]

All points on line should be on both planes but point B(5, -1, 4) does not belongs to planes.

[hafsaimtiaz]

Okay...those numbers which r wid 't'