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If y= sec inverse[1/2x sq. -1], 0 less than x less than 1/√2, find dy/dx.(+2.M76.HUKAM RAJ BHAGAT.)
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If y equal to sec inverse [1/2x square minus 1],
0 less than x less than 1/√2, find dy/dx.
+2.M 76.
HUKAM RAJ BHAGAT.
@hukamrajbhagat9437.
0 less than x less than 1/√2, find dy/dx.
+2.M 76.
HUKAM RAJ BHAGAT.
@hukamrajbhagat9437.