Derivative Shortcut Tricks #3 #shorts #dineshsirlivestudy

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Board checker :
Ruk beta abhi tera game bjata hu

xplainedezily
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For boards, You can solve it by Taking Log On Both Sides....

srujanbolewar
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"Hogya kya??"
"Ruk ruk ruk"
Litreally impatient me and my patient teacher😂

itznikiswifeu
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Let y = sinx^sinx
Taking log both sides
log y = sinx log(sinx)
Applying product rule
1/y( dy/dx) = sinx( 1/sinx)cosx + log(sinx)cosx
Cosx is common taking outside
dy/dx = y[ 1 + log(sinx)] cosx
dy/dx = sinx^sinx [ 1 + log(sinx)] cosx

Jisko bhi nahi samjh aaya to jakar padhai kar lo😂

Or commerce or science khelna band karo

lmgames
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Both side take log
And apply log property
After that apply differentiation product formula

Ajaymauryakxh
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You may use x^x formula that's x^x(1+logx) and just derivative of sinx
It's not trick it's simple mind calculation

Jee-ozzs
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Sir. Ase hi baki solutions ke short videos banayiye plz 🙏
For 12th cet

harishpatil
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Sir main toh fan hogaya 😌😂🥺 mujhe bhi apne team main lelo 😂

khanfaisal
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"Ruk Ruk Ruk", had me cracking up 😂

priyanshu__
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Who all are commerce student still watching and can't understand anything 😂😂

AKSKYGAMING
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Variable ki power ne variable....d/dx x^x =x^x ( 1+logx) ×1

Tanish
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Sir you are very best. You teach student in free of cost

krushnanavale
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Kitna easy karke bataya sir aap ne waw😊

shvetadeshmukh
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sir pehi baar apki trick se zyada easy ki hum uska derivative hi nikaal le

postapocalypticperson
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This process is valid for any f^g. Let u = differentiate it taking f constant, v = differentiate it taking g constant, add both

aryandhiman
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Thanku sir scroll karte karte kuch sikh liya

karan
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Sir it's really the easiest trick..😁
Thank you

Strawbellbee
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For boards
Take log on both sides
Log(y)=sinx•log(sinx)
Differentiating w.r.t.x
+ log(sinx)d(sinx)/dx
Dy/dx=y(cosx+cosx•log(sinx)
dy/dx=y(cosx(1+log(sinx)

MohammadShams-tw
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Sir my to dekh ker hi ker diya toda sa time lga

sundaramverma
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It's not shortcut it's just you have used analogy of x^x derivative which is x^x(1+logx) here x will be sin function but we will multiply with derivative because we have let it as x

steven-fqlv