How to prepare 1M HCl solution | Preparation of 0.1M HCl solution

Hello everyone,

Standard solution preparation forms the basis of practical chemistry. Here preparation of 1M HCl standard solution is shown. As HCl is available in concentrated liquid form , we have to first convert the molar mass equivalent to volume contained in given % assay in the stock solution i.e. concentrated solution in bottle. So first we shall find out the factor and then calculate required Volume for a given Molar or Normal solution as HCl has same molecular weight and equivalent weight being a monobasic acid.

#1MHClstandardsolution

Happy Learning.

[KhushbooKumari-mxsk]

Thank you so much.You explained the calculations splendidly.

[ranjansamal]

Very nicely explained Madam. Thank you very much. Kindly explain for 1 N HCL

[kingapex]

Just what I needed 🙏l have been looking for this explanation to solve these exact question for the past 3days

[syed]

Thnk you very much for explaining explicitly

[АлексейКузнецов-зкэ]

For the video at 0:51, it was said that molecular weight is 36.5 g/mL. But it's not correct, because molecular weight is measured at g/mole.

[pavadaiarumugam]

2nd formula is easier for me mam. Thank you so much

[PinkylovesAnimalsalot]

Excellent job maam but i don't understand how to prepare 0.1M HCl in 250 ml from 100% stock solution of HCl
Because according to my calculations Answer is 7.7

[ynhuo]

The 2nd, you said that 1dm^3 = 1000ml, if we take 1000/100 from 37% so we remain 10, and the equation become (1×36.5×10)/ 37×1.18

[sagarpatel]

Molecular weight = gram / mole you can write gram/ ML is not correct.🙏

[feziwewillams]

Great video, thank you. I want to prepare a 100 ml 25% v/v glutaraldehyde solution and the glutaraldehyde available is 50% wt% glutaraldehyde in water, MW= 100.12 g/mol, d= 1.106 g/ml. Would I be correct for using C1V1= C2V2. The answer I get is 50 ml of 50% glutaraldehyde in 100 ml to give 25% v/v glutaraldehyde. Thanks

[NaveenKumar-sxfn]

Ek video 1% HCl ke liye bhi bnaye mam thank you.

[souravrick]

Please correct the formula I think there is some mistake in it..with the first calculation the molarity can be calculated correctly..but the formula in the second case does not give the correct molarity

[د.محمدفكري-لق]

Thank you very much for your kind Explanation

[harishkumarbio]

For 100% = 30.9 x100/37

But for 37% = 30.9 ml.... Why it Should not be 37%=30.9x37