EdX Quantum Teleportation

[JohnSmith-veit]

Way above my thank god we have such smart people

[maxwellsdaemon]

At 3:03, inside the box labeled "STATE 2", why did the CNOT flip the 3rd bit (Bob's bit) instead of the 2nd bit?

[RahulAnand-pr]

1/root(2) [a|000>+a|011>+b|100>+b|111>]
applying cnot where q1 is target and q2 & q3 are targets, we get
1/root(2) [a|000>+a|011>+b|111>+b|100>]

but how are you getting
1/root(2) [a|000>+a|011>+b|101>+b|110>]

[jacobvandijk]

A bit more energy and enthusiasm in the presentation wouldn't have hurt this video.

[tom-stein]

Thanks for sharing, good explanation of the principle. However, I don' get what the purpose of this is: if we have to transfer a qBit of the entangled pair to Bob, why don't we just transfer |Ψ> directly?
Is is just because we can share the entangled pair in advance and come up / compute |Ψ> after that and then teleport? Even if that is the case we still have to wait for the classical information to be transferred, which likely takes the same amount of time as transferring a qBit.