2 Linear Equations in One Variable | Exercise - 2.5 | P2 | Q2 - Q5 | 8th Claass Maths | Chapter - 2

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All 8th Class Mathematics Text Book Solutions for Telugu and English Medium Students ( TS & AP ) from Nivas Info
8వ తరగతి గణితం ఆధ్యాయం - 2 ఏకచరరాశిలో రేఖీయ సమికరణాలు అభ్యాసం - 5

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Introduction to Linear Equations in One Variable

The linear equations in one variable is an equation which is expressed in the form of ax+b = 0, where a and b are two integers and x is a variable and has only one solution. For example, 2x+3=8 is a linear equation having a single variable in it. Therefore, this equation has only one solution, which is x = 5/2. Whereas if we speak about linear variable in two variables, it has two number of solutions.

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In This Chapter :

Introduction Linear Equations in One Variable,
Linear Equations,
Simple equations or Linear equations in one variable,
Solving Simple equation having the variable on one side,
Solving equation that has variables on both the sides,
Reducing Equations to Simpler Form - Equations Reducible to Linear Form,

Important Notes :

1. If the degree of an equation is one then it is called a linear equation.
2. If a linear equation has only one variable then it is called a linear equation in one variable or simple equation.
3. The value which when substituted for the variable in the given equation makes L.H.S. = R.H.S. is called a solution or root of the given equation.
4. Just as numbers, variables can also be transposed from one side of the equation to the other side.

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Sir.. meru cheppidhi chala baagaa. aatham aaeidhii sir.. chala baaga kuda explain chesaru... Tq soo much sir...

lachibandaru
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Super teaching sir and super explanation sir

siddidurgaprasad
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Nice explanation sir..but once see the 4th problem I think you thought that xx1 but it's x+1

thamme.praveenpraveen
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Sir meeru cheppedi chala baga ardham avuthundi
Thank u sir

vamaravellisomeswarrao
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Sir 4th problem answer lo numerator spelling thappu sir nominater ani raasaru
And super teaching sir

padmavathigangavarapu
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It's really very useful information

gayathrikumpilla
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Pls put the video of 4th chapter Exponents and power all exercises

siddidurgaprasad
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Sir thanks a lot endhukante naku ma teacher e problem homework ga echharu naku ardham kaledhu appudu ma friend mi channel chappadu andhuke nenu mi video chusanu.kani ma teacher kante kuda meru chaala baga chepparu

And thank you thank you very much

Rakshitha-
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Sir 4th problem your answer wrong sir x+1 =x how is it possible. I can try this problem sir 2(x-3)=1(x+1) its expansion is currently sir, you can see the problem 4 don't misunderstanding sir your not mistake sir its printing mistakes so can i tell you sir your mistakes thanking for your videos

motivationalstatus
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Sir which table you cut 21800 /436 in 5th sum

rohithputta
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Sir don't mine 4th answer is 3/7 because x+1=2x-6
X=7

hwnhbgj
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Madam you teaching so nice first time I watching your video so I like this video and I can understand so easily thankyou so much, Adam for this video

rangababu
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In 4th problem, x=7, fraction =3/7
But sir u did in different way, got same answer

sukumarsir
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Sir iam Lavanya all subjects project work give me Sir please 🙏🙏😭🙏😭

lavanyacreations
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5 th sum last from which table division sar

bhaskarganga
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That is'nt nominator it's numerator

vijayalakshmiravella
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4th prb lo... Denominater ki +1 add chesi prb cheyali... Bcz... +1 must be add cheyali.. skip cheyoddu... Appudu last lo direct ans vastundi.... Meeru +1 ki value evvakapothe last lo Kuda 6 ki +1 cheyakudadu Kada...
Naa comment ardham ayindanukuntunna ... TQ 🙂

shaikdilshad
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Miru 4th problem wrong chesaru okasari chudukondi
X+1 appudu X kaledu X*1aithe adi X avthadi ans Kuda wrong vachindi okasari correct chesukondi

laxmimeghavath
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Sir 4th sum meru nominator annaru adi nominator kadu numerator

yasaswini