🔴 Important JavaScript Interview #12: Program to Compare two Arrays are Equal or Not in JavaScript

Welcome, 🔴 Important JavaScript Interview #12: Program to Compare two Arrays are Equal or Not in JavaScript

The every() method tests whether all elements in the array pass the test implemented by the provided function. It returns a Boolean value.

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[jpwebdev]

arr1 = [1, 1, 2],
arr2 = [1, 2, 2]

these two are different arrays but your code shows them equal

[aweshkhan]

Sir make a ecommerce website with nodejs express and mongodb fetch products details, img, etc. We really need this type of contents

[chandreshkumar]

function compareArray(arr1, arr2) {

if (arr1.length != arr2.length)
{
return false
}
else {
for ( let i=0; i <arr1.length; i++){
if(arr1[i] != arr2[i]){
return false
}
}
return true;
}

}

let arr1 = [4, 8, 10, 9, 5];
let arr2 = [5, 10, 8, 9, 4];


let result = compareArray(arr1, arr2);
if (result) {
console.log("both are equal");
} else {
console.log("both are not equal");
}

[priyakarn]

apke tutorial se bahut kuch sikhne ko milta hai thanku so much sir 😀😀

[mohit]

core coding without any pre defined function =>

const main = (arr, arr2) =>{
const map ={};
const map2 = {}

for( item of arr ){
map[item] = (map[item]||0)+1
}
for( item of arr2 ){
map2[item] = (map2[item]||0)+1
}


console.log(map);
console.log(map2);

for( key in map){

if( map[item]!== map2[item] ){
return false
}else{
return true
}

}

}


console.log( main([4, 8, 10, 9, 5], [5, 10, 8, 9, 4]));

[ujjwalsrivastava]

we can do this way as well
for example :-
const array1 =[2, 6, 9, 3, 1];
const array2 =[3, 6, 1, 9, 2];

const arrayComparison = array1.length == array2.length &&
console.log(arrayComparison);

[muhammadsalmanalam]

Sir kindly yeh bata dein k JavaScript seekhnay k baad konsi pehlay karon aur phir pattern wise kia karon MERN Stack mein se
1. MongoDB
2. Express.js
3. React.js
4. Node.js

[maulik]

what if we sort both array and convert them into string and then compare both strings?🤔

[Tima-qlon]

const isSame = (arr1, arr2)=>{
return a1.length === a2.length &&
a1.every( cV => a2.indexOf(cV) >-1 )
}

👉Try this one for compare two array✌✌

[praveenkumar]

You can also compare two arrays using JSON.stringify().

JSON.stringify(array1) == JSON.stringify(array2)

[NiteshYadav-dglh]

After completing this series

Vinod Sir😀
Please!!🙏🙏
Upload the CRUD operations in Firebase with React.

Vinod sir there is many youtuber but no one can explain than you .

Because you are Awesome ❤️❤️

[adityajaiswar]

let arr = [2, 4, 6, 8];
let arr2=[8, 6, 4, 2]

let isSame = arr.length===arr2.length && arr.every((value)=>{

return value
}
})
console.log(isSame)
//Output will be true

[djayrok]

One of the best tutor I found in my life for learning programming concepts thanks alot sir.... Bcoz of u today I knew everything abt basics of javascript ❤

[adityajaiswar]

Instead of indedexOf () method we can use includes () method.
btw the thanks sir.

[siddiquiaffan]

Why you've used indexOf and why not includes() ?

[AnilSingh-ultc]

Just put array1 =[4, 4, 8, 10, 9]
In the same code and u will know this code is a joke.

[benkkstudio]

i think this is complicated, we should runa a loop to get each value from first array and a inner loop to check the value if its present in the second loop or not simple

[mdmustaqahmed]

Bhaiya iska time complexity O(n^2) ata hai i guess. we can do array objects implentation with O(n).

[vamshi_travelling_life]

Here you should compare the value (===) but in ur case you are assigning (=) but why its returning true am not getting

[LifeAtMH]

I think below is the refactored code. I don't think inner indexOf() is required. Correct me if I am wrong.

var arr1 = [10, 11, 12, 13];
var arr2 = [13, 12, 11, 10];

const is_len_same = arr1.length == arr2.length && arr1.every((curr_elem) => {
if(arr2.indexOf(curr_elem) > -1) {
return true;
}
})

console.log(is_len_same);